Answer:
25 units
Step-by-step explanation:
Applying Pythagoras' Theorem,
(BD)^2= (CD)^2 + (BC)^2
(BC)^2= 65^2 - 60^2
(BC)^2= 625
BC= √625= 25
Answer:

Step-by-step explanation:
We are given that a student needs to make a square cardboard piece.
Perimeter of cardboard should be equal to atleast 92 inches
We have to find that which shows reasonable domain for f(s)
Let s be the side of square cardboard
We know that perimeter of square =f(s=)
Then, perimeter of cardboard=

Dividing by 4 on both sides

Hence, the domain of function
Therefore, option d is true.
Answer:d: 
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Algebra
Factor
Factor the polynomial.
(
x
+
3
)
(
x
+
5
)
Tap to view FREE steps...
()|[]ó
789≤
456/^×>∩∪
123-+÷<π∞
,0.%=
Factor
x
2
+
8
x
+
15
+
0
Regroup terms.
x
2
+
0
+
8
x
+
15
Add
x
2
and
0
.
x
2
+
8
x
+
15
Factor
x
2
+
8
x
+
15
using the AC method.
Tap for fewer steps...
Consider the form
x
2
+
b
x
+
c
. Find a pair of integers whose product is
c
and whose sum is
b
. In this case, whose product is
15
and whose sum is
8
.
3
,
5
Write the factored form using these integers.
(
x
+
3
)
(
x
+
5
)
Answer:
A) 
B) - 5
C) Not Possible
D) 5
E) 
- Step-by-step explanation:
- All integers are rational numbers. But not all rational numbers are integers.
- All whole numbers are integers. But not all integers are whole numbers.
I am a rational number but not an integer. Located on the right of 0.
This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form
.
From, the options
would fit this description.
I am a rational number and an integer but not a whole number.
This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.
I am a whole number but not an integer.
This is clearly not possible because all whole numbers are a subset of integers.
I am a rational number, a whole number and an integer.
This means it is a positive integer. 5 would fit this description.
I am a rational number but not an integer; located on the left side of 0.
This means it is a negative number.
should be the answer.