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Lunna [17]
3 years ago
10

Evaluate x+x-x for x=4

Mathematics
1 answer:
Dafna1 [17]3 years ago
3 0
The answer is x=4 because 4+4 is 8 and 8 minus 4 is 4
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A linear function is modeled with y = 3x + 7. Is the point (4, 6) on the graph of the line?
Crank
Slope: 3

y-intercept: (0,7)

8 0
3 years ago
Hi can someone help me with this
Ad libitum [116K]

Answer:

25 units

Step-by-step explanation:

Applying Pythagoras' Theorem,

(BD)^2= (CD)^2 + (BC)^2

(BC)^2= 65^2 - 60^2

(BC)^2= 625

BC= √625= 25

5 0
3 years ago
A student needs to make a square cardboard piece. The cardboard should have a perimeter equal to at least 92 inches. The functio
Illusion [34]

Answer:

s\geq 23

Step-by-step explanation:

We are given that a student needs to make a square cardboard piece.

Perimeter of cardboard  should be equal to atleast 92 inches

We have to find that which shows reasonable domain for f(s)

Let s be the side of square cardboard

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Then, perimeter of  cardboard=4s

4s\geq 92

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s\geq 23

Hence, the domain of function[23,\infty)

Therefore, option d is true.

Answer:d: s\geq 23

6 0
3 years ago
Solve by factorizing x² + 8x + 15 + 0
shusha [124]

Download

GET

Algebra

Factor

Factor the polynomial.

(

x

+

3

)

(

x

+

5

)

Tap to view FREE steps...

()|[]√≥

789≤

456/^×>∩∪

123-+÷<π∞

,0.%=

Factor

x

2

+

8

x

+

15

+

0

Regroup terms.

x

2

+

0

+

8

x

+

15

Add

x

2

and

0

.

x

2

+

8

x

+

15

Factor

x

2

+

8

x

+

15

using the AC method.

Tap for fewer steps...

Consider the form

x

2

+

b

x

+

c

. Find a pair of integers whose product is

c

and whose sum is

b

. In this case, whose product is

15

and whose sum is

8

.

3

,

5

Write the factored form using these integers.

(

x

+

3

)

(

x

+

5

)

4 0
3 years ago
Read 2 more answers
I need #14 done by tomorrow around 9-10:00. Thank you so much if you do. God bless you :3
Vinvika [58]

Answer:

A) $ \frac{1}{5} $

B) - 5

C) Not Possible

D) 5

E) $ \frac{-1}{5} $

  • Step-by-step explanation:
  • All integers are rational numbers. But not all rational numbers are integers.
  • All whole numbers are integers. But not all integers are whole numbers.

I am a rational number but not an integer. Located on the right of 0.

This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form $ \frac{p}{q} $.

From, the options $ \frac{1}{5} $ would fit this description.

I am a rational number and an integer but not a whole number.

This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.

I am a whole number but not an integer.

This is clearly not possible because all whole numbers are a subset of integers.

I am a rational number, a whole number and an integer.

This means it is a positive integer. 5 would fit this description.

I am a rational number but not an integer; located on the left side of 0.

This means it is a negative number. $ -\frac{1}{5} $ should be the answer.

3 0
2 years ago
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