In this attached picture, we can prove that triangles AOB and COD are congruent. ∠CDO and ∠ABO are equal because they are alternate angles. Similarly, ∠OAB and ∠OCD are equal because they are alternate angles, as well. We have a rectangle and in the rectangle, opposite sides are equal; AB = CD. Then, because of Angle-SIde-Angle principle, we can say that triangles AOB and COD are equal. If triangles are congruent, then OD = OB and OC = AO. Applying congruency to the triangles ACD and BCD, we can see that these triangles are also congruent. It means that the diagonals are equal. Since, OD = OB and OC = AO, it proves that the point O simultaneously is the midpoint and intersection point for the diagonals.
Since a full circle has 360degrees and this circle only has two angles, subtract the arc of the known angle to find the arc of the unknown angle.
Angle DGF + angle DEF= 360degrees
Angle DGF + 70degrees= 360 degrees
Angle DGF = 290 degrees
The arc of the unknown angle is 290 degrees
Answer:
y-inctercept=4, x-intecept=7
Step-by-step explanation:
I did it with the standard to slope again!
Now don't get confused here, 4 is the y incetecept, not -4.
When y=0, x=7
UPDATE:
To determine x and y intercept using graph, see where the line intersects at the x or y axis.
Your most likely to land on tails because out of the 200 u landed on heads 14 times whereas u landed on tails 186 times since there's only two sides to a coin. there for you are more likely to land on tails than heads.
Answer:
they are side by side but not intersect
