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tankabanditka [31]
3 years ago
10

I WILL REWARD BRAINLIEST

Mathematics
2 answers:
Step2247 [10]3 years ago
4 0

Answer:

What is the total number of students who brought water bottles to lunch?

Step-by-step explanation:

lawyer [7]3 years ago
4 0

Answer:

What is the total number of students who brought water bottles to lunch?

Step-by-step explanation:

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Somebody please help me with this!
andreyandreev [35.5K]

8/x + 2 is equal to 8/4 + 2.

8/4 = 2

2 + 2 = 4

ANSWER: 4

5 0
3 years ago
Read 2 more answers
If f(x) = x, then f(64) is equal to<br><br> a. 1/4<br> b. -8<br> c. -4<br> d. 4
blsea [12.9K]
B hope it helps have a good day
6 0
3 years ago
Please help!!! Question is below
Lilit [14]

Answer:

A. Obtuse

Step-by-step explanation:

Well we can cross out C and D just by looking at the triangle because the triangle is not equal and there is no right angle.

Also it is not B an acute because not all the angles are acute.

Hence, the answer is A. Obtuse

8 0
4 years ago
Read 2 more answers
An umbrella has 12 evenly spaced ribs. If viewed as a flat circle of radius 11 units,
erica [24]

Answer:

Area = 121pi/12

~= 31.66 sq units

Step-by-step explanation:

They are talking about looking at an umbrella like its a circle. The radius is 11 units. That is from the center to the edge.

Consecutive means "in a row" or "next to each other" The 12 "ribs" are the like skeleton structure in the umbrella. But they cut the umbrella into 12 areas. They are asking for the area of one "slice". It is 1/12 of the area of the whole circle.

Area of a circle is

A = pi × r^2

Area of one slice is 1/12 of the whole.

A(1 slice)

= 1/12× pi × r^2

See image.

4 0
3 years ago
In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,
aivan3 [116]

Answer:

Case 1:

AB = 30

BC = 50

Case 2:

AB = 15.9

BC = 36.7

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

AB^2 = AN^2 + BN^2

This gives:

AB^2 = 24^2 + 18^2

AB^2 = 576 + 324

AB^2 = 900

Take square roots of both sides

AB = \sqrt{900

AB = 30

To calculate BC, we consider ANC, where:

AC^2 = AN^2 + NC^2

40^2 = 24^2 + NC^2

1600 = 576 + NC^2

Collect like terms

NC^2 = 1600 - 576

NC^2 = 1024

Take square roots

NC = \sqrt{1024

NC = 32

So:

BC = NC + BN

BC = 32 + 18

BC = 50

Case 2:

Using Pythagoras theorem in ANB, we have:

AN^2 = AB^2 + BN^2

This gives:

24^2 = AB^2 + 18^2

576 = AB^2 + 324

Collect like terms

AB^2 = 576 - 324

AB^2 = 252

Take square roots of both sides

AB = \sqrt{252

AB = 15.9

To calculate BC, we consider ABC, where:

AC^2 = AB^2 + BC^2

40^2 = 252 + BC^2

1600 = 252 + BC^2

Collect like terms

BC^2 = 1600 - 252

BC^2 = 1348

Take square roots

BC = \sqrt{1348

BC = 36.7

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0
3 years ago
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