Answer:
the answer is C... 100 m2
Step-by-step explanatii just took the test and it was right. the base would be 20 and the height would be 10. from there you just you the formula for area of a right triangle.
Answer:
Problem B: x = 12; m<EFG = 48
Problem C: m<G = 60; m<J = 120
Step-by-step explanation:
Problem B.
Angles EFG and IFH are vertical angles, so they are congruent.
m<EFG = m<IFH
4x = 48
x = 12
m<EFG = m<IFH = 48
Problem C.
One angle is marked a right angle, so its measure is 90 deg.
The next angle counterclockwise is marked 30 deg.
Add these two measures together, and you get 120 deg.
<J is vertical with the angle whose measure is 120 deg, so m<J = 120 deg.
Angles G and J from a linear pair, so they are supplementary, and the sum of their measures is 180 deg.
m<G = 180 - 120 = 60
Answer:
1725ft^2
Step-by-step explanation:
Hi!
First you have to find your two bases B1 and B2, which are 50 and 65.
Then you find the height, which is 30ft.
Finally, you plug those into the equation 1/2*h*(B1+B2) and solve.
1/2*30*(50+65)
1/2*30*(115)
15*115
1725ft^2 is your answer.
I hope this helps!
