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stiks02 [169]
2 years ago
15

A recent survey suggests that 85% of college students have a job, 54% live on campus, and 42% have a job and live on campus. Wha

t is the probability that a randomly chosen college student either has a job or lives on campus
Mathematics
1 answer:
OLga [1]2 years ago
3 0

\frac{97}{100} probability that a randomly chosen college student either has a job or lives on campus.

What is probability?

  • Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true.
  • The probability of an event is a number between 0 and 1, where 0 denotes the event's impossibility and 1 represents certainty.

To find the probability that a randomly chosen college student either has a job or lives on campus:

Given: 85% of college students have a job, 54% live on campus, and 42% have a job and live on campus.

So, out of 100 students, 42 students either has a job or live on campus.

43 college students have a job and 12  live on campus.

So, 43 + 42 + 12 = 85 + 54 - 42

85 + 12 = 139 - 42

97 = 97

Therefore, \frac{97}{100} probability that a randomly chosen college student either has a job or lives on campus.

Know more about probability here:

brainly.com/question/24756209

#SPJ4

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(HELP ASAP PLEASE!!)
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Answer:

Each shirt cost $<u>7</u>  and each pair of shorts cost $<u>17</u> .

Step-by-step explanation:

let shirts be represented as x

let shorts be represented as y

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4 x + 3 y = $79    .......equation 1

Older brother purchased 7 new shirts and 8 pairs of shorts and paid a total of $185.

7 x + 8 y = $185  .......equation 2

multiply equation 1 by 7 and equation 2 by -4 and add both equations to get the value of y.

7 × (4 x + 3 y = $79)     ⇒             +28 x + 21 y = $553

-4 × (7 x + 8 y = $185)  ⇒             <u> -28 x - 32 y = - $740</u>

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y = \frac{- $187}{- 11}   ⇒   y = $17

shorts = y = $17

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Shirts = x = $7

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