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stiks02 [169]
2 years ago
15

A recent survey suggests that 85% of college students have a job, 54% live on campus, and 42% have a job and live on campus. Wha

t is the probability that a randomly chosen college student either has a job or lives on campus
Mathematics
1 answer:
OLga [1]2 years ago
3 0

\frac{97}{100} probability that a randomly chosen college student either has a job or lives on campus.

What is probability?

  • Probability is an area of mathematics that deals with numerical descriptions of how probable an event is to occur or how likely a statement is to be true.
  • The probability of an event is a number between 0 and 1, where 0 denotes the event's impossibility and 1 represents certainty.

To find the probability that a randomly chosen college student either has a job or lives on campus:

Given: 85% of college students have a job, 54% live on campus, and 42% have a job and live on campus.

So, out of 100 students, 42 students either has a job or live on campus.

43 college students have a job and 12  live on campus.

So, 43 + 42 + 12 = 85 + 54 - 42

85 + 12 = 139 - 42

97 = 97

Therefore, \frac{97}{100} probability that a randomly chosen college student either has a job or lives on campus.

Know more about probability here:

brainly.com/question/24756209

#SPJ4

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A group of people help each other cope with a particular problem.
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Se tiene un lote baldío de forma triangular bardeado. La barda de enfrente tiene una medida de 4 m,las otras dos bardas no es po
dybincka [34]

Answer:

a) La medida de la barda que está enfrente del ángulo 64° es de, aproximadamente, 6.4292m. b) El triángulo en cuestión <em>no es un triángulo rectángulo</em>, es decir, ninguno de sus ángulos internos es <em>recto </em>(90 grados sexagesimales). En estos casos, no se puede aplicar el Teorema de Pitágoras o la simple utilización de las razones trigonométricas; se aplican, en cambio, leyes para la resolución de triángulos oblicuángulos (o triángulos no rectángulos).

Step-by-step explanation:

Este problema no se puede resolver "aplicando sólo las razones trigonométricas o el teorema de Pitágoras" porque es sólo aplicable a <em>triángulos rectos</em>, es decir, uno de los ángulos del triángulo es recto o igual a <em>90</em> grados sexagesimales. Los dos restantes triángulos suman 90 grados sexagesimales, o se dice, son <em>complementarios</em>.

La resolución de triángulos que no son rectos (conocida en algunos textos como solución de problemas de triángulos oblicuángulos) pueden resolverse usando, la <em>ley de los senos (o teorema del seno)</em>, <em>ley de los cosenos</em> y <em>la ley de las tangentes</em>. El caso propuesto en la pregunta se ajusta a la <em>ley de los senos</em>:

\\ \frac{a}{\sin(\alpha)} = \frac{b}{\sin(\beta)} = \frac{c}{\sin(\gamma)}

Es decir, la razón entre el lado de un triángulo y el seno del ángulo que tiene frente a él es igual para todos los lados y ángulos del triángulo.

El triángulo de la pregunta no tiene un ángulo recto

La suma de los ángulos internos de un triángulo es de 180 grados sexagesimales:

\\ \alpha + \beta + \gamma = 180^{\circ}

En la pregunta tenemos que la suma de los dos ángulos propuestos es:

\\ 34^{\circ} + 64^{\circ} + \gamma = 180^{\circ}

\\ 98^{\circ} + \gamma = 180^{\circ}

Restando 98 grados sexagesimales a cada lado de la igualdad:

\\ 98^{\circ} - 98^{\circ} + \gamma = 180^{\circ} - 98^{\circ}

\\ 0 + \gamma = 180^{\circ} - 98^{\circ}

\\ \gamma = 82^{\circ}

Con lo que se deduce que no hay ningún ángulo recto en el triángulo propuesto y no se podría usar el Teorema de Pitágoras o simples razones trigonométricas para resolverlo.

Resolución del lado del triángulo

De la pregunta tenemos:

  • La barda de enfrente tiene una medida de 4m. El ángulo que está enfrente de esta barda (barda frontal) es de 34°.
  • No se sabe el valor del lado que está enfrente del ángulo de 64°, pero se puede calcular usando la Ley de los senos.

Digamos que:

\\ a = 4m, \alpha = 34^{\circ}

\\ b = x, \beta = 64^{\circ}

Entonces, aplicando la <em>Ley de los senos</em>:

\\ \frac{a}{\sin(\alpha)} = \frac{b}{\sin(\beta)}

Multiplicando a cada lado de la igualdad por \\ \sin(\beta)

\\ \frac{a}{\sin(\alpha)}*\sin(\beta) = \frac{b}{\sin(\beta)}*\sin(\beta)

\\ \frac{a}{\sin(\alpha)}*\sin(\beta) = b*\frac{\sin(\beta)}{\sin(\beta)}

\\ \frac{a}{\sin(\alpha)}*\sin(\beta) = b*1

\\ \frac{a}{\sin(\alpha)}*\sin(\beta) = b

Sustituyendo cada valor en la expresión anterior:

\\ b = \frac{a}{\sin(\alpha)}*\sin(\beta)

\\ b = \frac{4m}{\sin(34^{\circ})}*\sin(64^{\circ})

\\ b = 4m*\frac{0.8988}{0.5592}

\\ b = 6.4292m

En palabras, la medida de la barda que está enfrente del ángulo 64° es de, aproximadamente, 6.4292m.

El lado <em>c</em> puede obtenerse de manera similar considerando que \\ \gamma = 82^{\circ}.

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konstantin123 [22]

Answer:

(a) = 0.32 or 8/25

(b) = 0.48 or 12/25

(c) = 4 Boards

Step-by-step explanation:

(a):

0.8 x 2/5

8/10 x 4/10

(8 x 4) / (10 x 10)

(32) / (100)

0.32 or 8/25

(b):

0.8 x 3/5

8/10 x 6/10

(8 x 6) / (10 x 10)

(48) / (100)

0.48 or 12/25

(c):

0.8 x 5

8/10 x 50/10

(8 x 50) / (10 x 10)

(400) / (100)

4 Boards

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musickatia [10]

Answer:

$148.50

Step-by-step explanation

I solved this by using fractions.

x/450=33/100 is how I set up the problem. 33/100 represents 33%, while x/450 represents how much the jacket costs now.

I then went across and multiplied x by 100, and 450 by 33, which gave me 100x=14850. After this I divided each side by 100 to get 148.5, being the cost of the jacket.

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