Answer:
P₂ = 2541.24 kPa
Explanation:
The pressure can be find using the law of gases and fluids of the thermodynamic so:
Δ P = ¹/₂ * γ / g * ( V₂² - V₁² )
V² = u² + v²
Solving using the equation
φ = 2 x² * y - ²/₃ * y ³
At the point (1.1)
u = 4 * x *y ⇒ u₁ = 4 * 1 * 1 = 4 m/s
v₁ = 2x² - 2y² ⇒ v₁ = 2 * 1² - 2 * 1² = 0
V₁² = 4² + 0² = 16 m² / s²
At the point (1,7 . 1,7)
u = 4 * x *y ⇒ u₁ = 4 * 1.7 * 1.7 = 11.56 m/s
v₂ = 2x² - 2y² ⇒ v₂ = 2 * 1.7² - 2 * 1.7² = 0
V₂² = 11.56² + 0² = 133.6336 m² / s²
Replacing
Δ P = ¹/₂ * γ / g * ( V₂² - V₁² ) ⇒ P₁ - P₂ = ¹/₂ * γ / g * ( V₂² - V₁² )
P₂ = P₁ + 0.5 * γ / g * ( V₂² - V₁² ) ⇒ P₂ = 2600 kPa + 0.5 * 9.8 x 10³ / 9.8 m/s₂ * ( 16 - 133.6336 )
P₂ = 2541.24 x 10³ Pa
P₂ = 2541.24 kPa
Answer:
1, 2, 4, 5, 6, 8
Explanation:
1. 2 N; 2 N
2. 200 N; 200 N
3. 200 N; 201 N
4. 2 N; 2 N; 4 N
5. 2 N; 2 N; 2 N
6. 2 N; 2 N; 3 N
7. 2 N; 2 N; 5 N
8. 200 N; 200 N; 5 N
The net force of the system should be 0 in order for the body to move at a constant velocity.
So, the options 1, 2, 4, 5, 6, 8 have net force equal to zero so they are possibly maintaining the speed of 256 m/s
Answer:
B. Titanium alloy rod
Explanation:
Attached is the full solution
Answer:
The centripetal on the car will become 4 times when the velocity gets twice.
Explanation:
As we know that centripetal force on the car of mass m and moving with constant speed v given as
m=mass
v=velocity
r=radius of the circular arc
We are assuming that the mass of the both the car is same.
If the velocity of the car gets twice 2 v
The new centripetal force on the car
Therefore we can say that centripetal on the car will become 4 times when the velocity gets twice.
A delightful problem !
I'm pretty sure that what we need here is the speeds, not the velocities,
and that's the way I'm going to do it.
Regular speed is (distance covered) divided by (time to cover the distance) .
Angular speed is very much the same.
It's
(angle turned) divided by (time to turn the angle) .
<u>Earth's orbit around the sun</u>:
..... Once per year.
..... Roughly 360° in 365 days ..... <em>almost exactly 1° per day</em>.
Let's see what it is more accurately:
(360°) / (<span>365.25636<span> days) = 0.985609° per day.
============================================
<u>Earth's rotation on its axis</u>:
..... Once per "day".
..... Roughly 360° in 24 hours ..... <em>almost exactly 15° per hour</em>.
This one is slightly trickier to do more accurately, because a day is
not necessarily 24 hours. It depends on what you call 1 day.
-- If you say the day is the period of time between when the sun is
highest in the sky, then that averages out to 24 hours in the course
of a year.
-- If you say that the day is the period of time it takes for a star
to reach the same point in the sky tomorrow night, then that's </span></span>
23 hours, 56 minutes, 4.09 seconds .
Using this to calculate the angular speed of rotation, you get
(360°) / (23h 56m 4.09s) = 15.041° per hour