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kherson [118]
4 years ago
14

Thel speed of sound in water is 1498 m/s. A sonar signal is sent straight down from a ship at a point just below the water surfa

ce, and 2.50 s later reflected signal is detected. How deep is the water
Physics
1 answer:
lapo4ka [179]4 years ago
5 0
D =vt


since it has to go down and come back up, you must half the time in this problem.


d = (1498)(0.5•2.5)

d = 1872.5 m
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Please send me solution of the question pls​
ELEN [110]

Answer:

20m

Explanation:

P.E=mgh

2000=10×10×h

2000=100h

Divide both side by 100

2000/100=20

4 0
3 years ago
Please complete it if you know the answer. "The active region of a transistor is for.........
zubka84 [21]

Answer:

the active region is bound by cutoff region and saturation or power dissipation region.

Explanation:

5 0
3 years ago
A box has a mass of 400 g. What minimum force is needed to lift it?
mart [117]

Answer: 3.92 N.

Explanation:

Your box weighs 400g, or 0.4kg. In order to lift it, you need to overcome the force of gravity. F = ma, and acceleration due to gravity is -9.8 m/s^2. So gravity acts on the box with a force of 0.4 kg * -9.8 m/s^2 = -3.92 N. A force of +3.92 N is required to overcome this.

5 0
3 years ago
Please help
Snezhnost [94]

Answer:

Range = 22.61 m

Explanation:

We can use the formula for the Range in flat ground, given by:

Range=v_i^2\frac{sin(2\theta)}{g}

which for our case renders:

Range=15^2\frac{sin(80^o)}{9.8} \approx 22.61\,\,m

4 0
3 years ago
A<br> B <br> C <br> D<br><br> Plz help me.
Montano1993 [528]

Answer:

The correct option is;

{}               Man doing most work   {}    Box gaining the most energy

D   {}                 Y                                          Q

Explanation:

The given parameters of the question are;

The distance the box P is pushed by the Man X = 0

The force the Man X applies to the box P = x N

The distance the box Q is lifted by the Man Y = h > 0 meters

The minimum force the Man Y applies to the box Q = W, the weight of the box

Work done = Force × Distance

Energy gained = Potential energy + Kinetic Energy = (Mass × Gravity × Height = Weight × Height  = W × h) + 1/2 × Mass × Velocity²

The final velocity of either box = 0 m/s (The boxes are at rest on the ground or the shelf)

Therefore, Kinetic energy = 0 J

The work done by Man X = 0 × x = 0 J

The energy gained by the box P = W × 0 = 0 J

The work done by Man Y = W × h = W·h J

The energy gained by the box P = W × h = W·h J

We have, the work done by the man Y = W·h J is more than the work done by the man X = 0 J

The energy gained by the box P = W·h J is more than the energy gained by the box Q = 0 J

Therefore, the correct option is D, Man doing the most work is Y, box gaining the most energy is Q.

8 0
3 years ago
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