All categories

3 years ago

Peyton and Ashley have five red apples.peyton is holding five of the apples.how many is Ashley holding?

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

6 0

Ashley is holding nothing that is the answer.

yKpoI14uk [10]3 years ago

6 0

Ashley isn't holding any apples which would make the answer 0.

You might be interested in

What is 12+[(14-6)/4]

saveliy_v [14]

Answer:

Step-by-step explanation:

THE ANSWER TO THE PROBLEM IS 14

3 0

3 years ago

A company has introduced two new products to the market. The revenue generated by product A was $63,000 in the first year, and t

elena-s [515]

The correct answer is R(x) = 9,000[9(1.035)x + 7(1.021)x]; $170,936

6 0

3 years ago

Read 2 more answers

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$

Multiply both sides by 16:

$(16x^2+32x+16)+(9x^2-54x+81) = 256$

Combine like terms:

$25x^2+-22x+97=256$

Isolate the equation:

$\displaystyle 25x^2 - 22x -159=0$

We can use the quadratic formula:

$\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = 25, b = -22, and c = -159. Substitute:

$\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}$

Evaluate:

$\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}$

Hence, our two solutions are:

$\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}$

We have our two x-coordinates.

To find the y-coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

$\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2$

And:

$\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}$

Thus, our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

6 0

3 years ago

loyd is playing a game where he is trying to roll a 3 with a standard die. If he gets a 3 in any of his first 8 rolls, he wins;

Komok [63]

The probability would probably be 1/8

8 0

2 years ago

Please help with this question thank you very much.

DochEvi [55]

Answer:

ln 3

Step-by-step explanation:

3 ln 3 - ln 9

We can rewrite 9 as 3^2

3 ln 3 - ln 3^2

We know lnx^a = aln x

3 ln 3 - 2 ln 3

ln 3

6 0

3 years ago