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Reil [10]
3 years ago
6

Which symbol correctly compares the two angle measures?

Mathematics
1 answer:
Mazyrski [523]3 years ago
4 0

Answer:

Is B

Step-by-step explanation:

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How do you find the slope of y+3=1/3(x+9)
Paraphin [41]

Answer:

y = −1/3x + 10/3

Step-by-step explanation:

6 0
3 years ago
Given: circle k(O), m LM = 164°, m WK = 68°, m∠MLK = 65°. Find: m∠LMW
Musya8 [376]

Answer:

The measure of angle LMW is m\angle LMW=67\°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of arc MW

we know that

The inscribed angle measures half that of the arc comprising

so

m\angle MLK=\frac{1}{2}[arc\ MW+arc\ WK]

substitute the given values

65\°=\frac{1}{2}[arc\ MW+68\°]

130\°=[arc\ MW+68\°]

arc\ MW=130\°-68\°=62\°

step 2

Find the measure of arc LK

we know that

arc\ LM+arc\ MW+arc\ WK+arc\ LK=360\° -----> by complete circle

substitute the given values

164\°+62\°+68\°+arc\ LK=360\°

294\°+arc\ LK=360\°

arc\ LK=360\°-294\°=66\°

step 3

Find the measure of angle LMW

we know that

The inscribed angle measures half that of the arc comprising

so

m\angle LMW=\frac{1}{2}[arc\ LK+arc\ WK]

substitute the given values

m\angle LMW=\frac{1}{2}[66\°+68\°]=67\°

4 0
3 years ago
Base on the data what is the probability of rolling a 3 or a 5
Kobotan [32]

Answer:

1/3

Step-by-step explanation:

There are 6 numbers on a dice, you want one out of the 2 outcomes, so tat makes it 2/6 or 1/3 chance of rolling a 3, or a 5

3 0
4 years ago
Read 2 more answers
Given that <2=<6.
Misha Larkins [42]

Answer: B . Converse of the alternate exterior angle theorem.

5 0
4 years ago
A bag contains red marbles, white marbles, and blue marbles. Randomly choose two marbles, one at a time, and without replacement
dsp73

Answer:

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

P(Same) = \frac{67}{210}

Step-by-step explanation:

Given (Omitted from the question)

Red = 7

White = 9

Blue = 5

Solving (a): P(First\ White\ and\ Second\ Blue)

This is calculated using:

P(First\ White\ and\ Second\ Blue) = P(White) * P(Blue)

P(First\ White\ and\ Second\ Blue) = \frac{n(White)}{Total} * \frac{n(Blue)}{Total - 1}

<em>We used Total - 1 because it is a probability without replacement</em>

So, we have:

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{21 - 1}

P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{20}

P(First\ White\ and\ Second\ Blue) = \frac{9*5}{21*20}

P(First\ White\ and\ Second\ Blue) = \frac{45}{420}

P(First\ White\ and\ Second\ Blue) = \frac{3}{28}

Solving (b) P(Same)

This is calculated as:

P(Same) = P(First\ Blue\ and Second\ Blue)\or\ P(First\ Red\ and Second\ Red)\ or\ P(First\ White\ and Second\ White)

P(Same) = (\frac{n(Blue)}{Total} * \frac{n(Blue)-1}{Total-1})+(\frac{n(Red)}{Total} * \frac{n(Red)-1}{Total-1})+(\frac{n(White)}{Total} * \frac{n(White)-1}{Total-1})

P(Same) = (\frac{5}{21} * \frac{4}{20})+(\frac{7}{21} * \frac{6}{20})+(\frac{9}{21} * \frac{8}{20})

P(Same) = \frac{20}{420}+\frac{42}{420} +\frac{72}{420}

P(Same) = \frac{20+42+72}{420}

P(Same) = \frac{134}{420}

P(Same) = \frac{67}{210}

6 0
3 years ago
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