<span>C. Jewelry tarnishing is an example of a chemical change.
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Chemical change is a process where a current substance changes or is made into a new type of substance<span>. Unlike the physical change, which is reversible. Chemical change stays into a its new form. Take for instance these -physical change- examples, making ice cubes. The process involves solidification or freezing where the water becomes ice or solid but when it melts back to its original or typical form with respect to temperature, it’s still water. When the paper is cut into pieces it isn’t burned or exposed to a stimuli that can trigger immediate change in its composition. It’s still the same. On the contrary, baking a cake involves these different compositions or substances –flour, egg, yeast and etc. that is baked to a cake, a newly formed unified substance of all the included ingredients. <span> </span></span>
Answer:
The answer to your question is below
Explanation:
A.
[H₃O⁺] = 2 x 10⁻¹⁴ M
pH = ?
Formula
pH = - log [H₃O⁺]
Substitution
pH = - log [2 x 10⁻¹⁴]
Result
pH = 13.7
B.
[H₃O⁺] = ?
pH = 3.12
Formula
pH = - log [H₃O⁺]
Substitution
3.12 = - log [H₃O⁺]
Result
[H₃O⁺] = 7.59 M
Answer:
0 %
Explanation:
As we know 10.81 is the average atomic mass of boron which can not be contained by a single boron atom. Therefore, when isolated, a single boron atom will weight either 10 amu for ¹⁰B and 11 amu for ¹¹B respectively.
The average atomic mass is calculated as;
Atomic Mass of ¹⁰B = 10
Atomic Mass of ¹¹B = 11
Natural Abundance of ¹⁰B = 20 %
Natural Abundance of ¹¹B = 80 %
So,
Average Atomic Mass = (10 × 0.2) + (11 × 0.8)
Average Atomic Mass = 2 + 8.8
Average Atomic Mass = 10.8
A solid will always hold its shape as long as there are no item/forces acting on it.
Liquids, plasma, and gases will never hold a shape on there own, mostly all liquids only hold the shape there given. Gases never really have a shape.And plasma is a form of energy, so its more like the gas, it has to be given a shape/container.
Answer :B
Hope this helps
Answer:
1.23 j/g. °C
Explanation:
Given data:
Mass of metal = 35.0 g
Initial temperature = 21 °C
Final temperature = 52°C
Amount of heat absorbed = 320 cal (320 ×4.184 = 1338.88 j)
Specific heat capacity of metal = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 52°C - 21 °C
ΔT = 31°C
1338.88 j= 35 g ×c× 31°C
1338.88 j= 1085 g.°C ×c
1338.88 j/1085 g.°C = c
1.23 j/g. °C = c