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bija089 [108]
3 years ago
11

Non-polar covalent compounds can dissolve _______. A. polar covalent compounds B. ionic compounds C. non-polar covalent compound

s D. All of the Above E. None of the Above
Chemistry
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:non-polar covalent compounds

Explanation:

In chemistry, like compounds interact. If a solvent is covalent and nonpolar, it will also dissolve nonpolar covalent compounds. This is because, they contain similar patterns of intermolecular interaction. Hence compounds that posses the same kind of intermolecular interaction can form a solution.

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How many atoms of fluorine are in 5.6×1022 molecules of MgF2?
VashaNatasha [74]

Answer:You can set up stoichiemetry using the following equation:

(15.6 g MgF2) x (38g F / 62g MgF2) x (6.022x10^23 / 19gF)

= 3.03 x 10^23 molecules of F

or 1.52 x 10^23 molecules of F2

The number of molecules of magnesium fluoride in 15.6 g of MgF2 has to be found.

The molecular mass of MgF2 is 62.3018. 15.6 g of MgF2 is equivalent to 15.6/62.3018 mole of MgF2.

One mole of a gas has 6.02214179*10^23 particles.

15.6/62.3018 mole of MgF2 has (15.6/62.3018)*6.02214179*10^23 molecules of the compound.

(15.6/62.3018)*6.02214179*10^23

=> 1.5079*20^23

If this is rounded to one decimal figure the result is 1.51*10^23.

The number of molecules of MgF2 in 15.6 g of the gas is 1.51*10^23.

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3 years ago
What is the h+ oh- and poh of solution with ph=3.67
Alexxx [7]
Hi I don’t know the answer is I don’t know but I hope someone helps u ph=3.67
7 0
2 years ago
What domain is an onion
Nana76 [90]
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3 0
3 years ago
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What is the mass of an object with a net force of 10 N accelerating at 2 m/s^2??
xz_007 [3.2K]

Answer:

5kg

Explanation:

Force = Mass x acceleration

F = ma

m = F/a = 10N/2m/s^2

m = 10/2 = 5kg

The standard unit for mass = Kilogram

5 0
3 years ago
The pressure of a sample of argon gas was increased from 3.14 atm to 7.98 at a constant temperature. If the final volume of argo
noname [10]

Answer:

<h2>36.09 L</h2>

Explanation:

The initial volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume.

Since we're finding the initial volume

V_1 =  \frac{P_2V_2}{P_1}  \\

We have

V_1 =  \frac{7.98 \times 14.2}{3.14} =   \frac{113.316}{3.14}  \\  = 36.0878...

We have the final answer as

<h3>36.09 L</h3>

Hope this helps you

8 0
3 years ago
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