Answer:You can set up stoichiemetry using the following equation:
(15.6 g MgF2) x (38g F / 62g MgF2) x (6.022x10^23 / 19gF)
= 3.03 x 10^23 molecules of F
or 1.52 x 10^23 molecules of F2
The number of molecules of magnesium fluoride in 15.6 g of MgF2 has to be found.
The molecular mass of MgF2 is 62.3018. 15.6 g of MgF2 is equivalent to 15.6/62.3018 mole of MgF2.
One mole of a gas has 6.02214179*10^23 particles.
15.6/62.3018 mole of MgF2 has (15.6/62.3018)*6.02214179*10^23 molecules of the compound.
(15.6/62.3018)*6.02214179*10^23
=> 1.5079*20^23
If this is rounded to one decimal figure the result is 1.51*10^23.
The number of molecules of MgF2 in 15.6 g of the gas is 1.51*10^23.
Hi I don’t know the answer is I don’t know but I hope someone helps u ph=3.67
The domain that is an onion is the <span>Eukaryote.
</span>
Answer:
5kg
Explanation:
Force = Mass x acceleration
F = ma
m = F/a = 10N/2m/s^2
m = 10/2 = 5kg
The standard unit for mass = Kilogram
Answer:
<h2>36.09 L</h2>
Explanation:
The initial volume can be found by using the formula for Boyle's law which is

where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume.
Since we're finding the initial volume

We have

We have the final answer as
<h3>36.09 L</h3>
Hope this helps you