The surface area of a cylindrical can is equal to the sum of the area of two circles and the body of the cylinder: 2πr2 + 2πrh. volume is equal to π<span>r2h.
V = </span>π<span>r2h = 128 pi
r2h = 128
h = 128/r2
A = </span><span>2πr2 + 2πrh
</span>A = 2πr2 + 2πr*(<span>128/r2)
</span>A = 2πr2 + 256 <span>π / r
</span><span>
the optimum dimensions is determined by taking the first derivative and equating to zero.
dA = 4 </span>πr - 256 <span>π /r2 = 0
r = 4 cm
h = 8 cm
</span><span>
</span>
Answer:
6 units
Step-by-step explanation:
A = lw
l = w + 2
48 = lw
48 = (w + 2)w
48 = w² + 2w
0 = w² + 2w - 48
Quadratic equation results =
w = 6 or w = -8
But the measure could not be negative, therefore w = 6
A. 12x+y=6<span>B. −2x+y=6</span>
