When glucose is high, cAMP is low; CAP does not bind the lac operator, and RNA polymerase does not bind the lac promoter. CAP is only active when glucose levels are low, which means the cAMP levels are high, and therefore the lac operon can only be transcribed at high rate when glucose is absent. The importance of this is that the bacteria only turns on the lac operon and start using lactose only after they have used up all the preferred energy source which is glucose.
There's a first one, that's called the leading strand. Its the parens strand of the DNA which runs in the 3' to 5' direction to the fork.......
They are much like empty rooms false
the cell lacks a nucleus is true
the rest are wrong
Answer:
ΔG°' for the conversion of citrate to α-ketoglutarate = - 273.64 kJmol-1
Explanation:
ΔG°' for Citrate is +6.64 kJmol-1
ΔG°' for Isocitrate is -267 kJmol-1
ΔG°' for the conversion of citrate to α-ketoglutarate = ΔG°' for product - ΔG°' for reactant
ΔG°' for the conversion of citrate to α-ketoglutarate = -267 kJmol-1 - (+6.64 kJmol-1)
ΔG°' for the conversion of citrate to α-ketoglutarate = - 273.64 kJmol-1
it will be bumpy , ugly, and dirty
