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2 years ago

Would the height of a circle be considered the diameter?

Mathematics

2 answers:

aliina [53]2 years ago

5 0

Yes the height will be considered the diameter,from my knowledge

AnnyKZ [126]2 years ago

4 0

Yes the height of a circle could be considered the diameter

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The hypotenuse of a triangle is 37 millimeters long. One of the legs is 24.5 millimeters long. What is the measure of the missin

blsea [12.9K]

Answer: 27.7 millimeters

Step-by-step explanation:

Let the missing leg be represented by x.

We will use Pythagoras formula to solve this. The measure of the missing leg will be:

x² = 37² - 24.5²

x² = 1369 - 600.25

x² = 768.75

x = ✓768.75

x = 27.7

The missing leg is 27.7 millimeter

8 0

3 years ago

A. find the characteristic equation of

olga55 [171]

B
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5 0

3 years ago

What is the value of x in the equation below?

belka [17]

$remember$
$ln(a^b)=bln(a)$
$ln(e)=1$
$so$
$ln(e^x)=xln(e)=x$

$1+2e^{x+1}=9$
$minus \space\ 1 \space\ both \space\ sides$
$2e^{x+1}=8$
$divide \space\ both \space\ sides \space\ by \space\ 2$
$e^{x+1}=4$
$take \space\ ln \space\ of \space\ both \space\ sides$
$ln(e^{x+1})=ln(4)$
$(x+1)ln(e)=ln(4)$
$x+1=ln(4)$
$minus \space\ 1 \space\ from \space\ both \space\ sides$
$x=ln(4)-1$
$answer \space\ is \space\ C=ln(4)-1$

5 0

3 years ago

Read 2 more answers

What does two and five fiths equal to

erma4kov [3.2K]

2 and five fifths = 3

I hope that's help. Good night .

6 0

2 years ago

Read 2 more answers

Just need help on #7 thru 8(a), b and c

Stella [2.4K]

a. The slope of the line passing through the points R(3, 5) and H(-1,2) is -3/4

b. The distance between two points (x₁, y₁) and (x₂,y₂) is 5 units

c. The midpoint of the R(3, 5) and H(-1,2) is (2, 4)

a. The transformation rule is (x,y) → (x + 1, y - 1)

The x-coordinate is shifted 1 unit to the left and

The y - coordinate is shifted 1 unit downwards.

c. The image of B' the pre-image of B(5, 6) is (6, 5)

<h3 /><h3>7 a. How to find the slope of the line?</h3>

The slope of a line passing through the points (x₁, y₁) and (x₂,y₂) is m = (y₂ - y₁)/(x₂ - x₁)

Given that

(x₁, y₁) = (3, 5) and
(x₂,y₂) = (-1, 2)

So, m = (y₂ - y₁)/(x₂ - x₁)

m = (2 - 5)/(-1 - 3)

m = -3/-4

m = -3/4

So, the slope of the line passing through the points R(3, 5) and H(-1,2) is -3/4

<h3>b. The distance between the points</h3>

The distance between two points (x₁, y₁) and (x₂,y₂) is d = √[(y₂ - y₁)² + (x₂ - x₁)²]

Given that

(x₁, y₁) = (3, 5) and
(x₂,y₂) = (-1, 2)

d = √[(y₂ - y₁)² + (x₂ - x₁)²]

d = √[(2 - 5)² + (-1 - 3)²]

d = √[(-3)² + (-4)²]

d = √[9 + 16]

d = √25

d = 5 units

So, the distance between two points (x₁, y₁) and (x₂,y₂) is 5 units

<h3>7 c How to find the midpoint of the R(3, 5) and H(-1,2) </h3>

The midpoint of the the points (x₁, y₁) and (x₂,y₂) is (x, y) = [(x₁ + x₂)/2, (y₁ + y₂)/2]

Given that

(x₁, y₁) = (3, 5) and
(x₂,y₂) = (-1, 2)

So, the midpoint (x, y) = [(x₁ + x₂)/2, (y₁ + y₂)/2]

(x, y) = [(3 + (-1))/2, (5 + 3)/2]

(x, y) = [(3 - 1)/2, (5 + 3)/2]

(x, y) = [4/2, 8/2]

(x, y) = (2, 4)

So, the midpoint of the R(3, 5) and H(-1,2) is (2, 4)

<h3>8. a The rule for the transformation of point A(1, 4) to point B(2, 3)</h3>

Given that point A(1, 4) and point B(2, 3) we see that point B(1 + 1, 4 - 1).

Let pont A be (x,y).

So, point B = (x + 1, y - 1)

So, the transformation rule is (x,y) → (x + 1, y - 1)

<h3>b. Describe the transformation</h3>

Since the transformation rule is (x,y) → (x + 1, y - 1), we see that

the x-coordinate is shifted 1 unit to the left and
the y - coordinate is shifted 1 unit downwards.

<h3>c. The image of B' the pre-image of B(5, 6)</h3>

Since the transformation rule is (x,y) → (x + 1, y - 1) and point B is (5, 6), thus the image of B' is

(x,y) → (x + 1, y - 1)

(5,6) → (5 + 1, 6 - 1)

(5,6) → (6, 5)

So, the image of B' the pre-image of B(5, 6) is (6, 5)

Learn more about slope of a line here:

brainly.com/question/1617757

#SPJ1

3 0

1 year ago