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lubasha [3.4K]
3 years ago
15

Hellllllllllllllllllllllllllp

Mathematics
2 answers:
GuDViN [60]3 years ago
4 0

Answer:

sorry whats the question

Step-by-step explanation:

Vedmedyk [2.9K]3 years ago
4 0

5. w ≥ 30

6. m ≥ 45

7. t ≠ 21

8. c < 45

9. d > 1/5

10. s ≠ 45 5/6

11. h ≥ 45

12. p < 5

Word problem: s ≥ 35 subs to make a profit

Hope this helps!

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Simplify the expression below as much as possible (6-i)+(4+2i)-(-2+i)
Luba_88 [7]

Answer:

=6-i+4+2i+2-i

=6+4+2+2i-i-i

=12+2i-2i

=12

4 0
2 years ago
winthrop Middle School had enrollment of 1,342 and a total of 215 teachers. what was the student teacher ratio for this School w
eimsori [14]
Teachers= 215
Students= 1,342

Student: Techer
= 1,342: 215
= 62.1:1
= \frac{62.1}{1}
3 0
3 years ago
Read 2 more answers
What is 6y−12=−3x in standard form?
aalyn [17]
3x + 6y = 12.
In standard form.

5 0
3 years ago
Ben has 3 times as many guppies as goldfish. If she has a total of 20 fish how many guppies does she have
Thepotemich [5.8K]
Guppies 15
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7 0
3 years ago
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
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