First, you need to know 1 kg = 10^3 g. And 1 m^3 = 10^6 m^3. So the 1 g/cm3 = 10^3 kg/m3. So the answer is 1.93*10^4 kg/m3.
Answer:
The answer to your question is 24.32 g
Explanation:
Data
Atomic weight = ?
HCl volume = 125 ml
Molarity = 0.2
mass of metal = 0.304 g
Balanced chemical equation
M + 2HCl ⇒ MCl₂ + H₂
Process
1.- Calculate the moles of HCl
Molarity = moles / volume (L)
- Solve for moles
moles = Molarity x volume
moles = 0.2 x 0.125
= 0.025
2.- Calculate the moles of the Metal
1 mol of M ----------------- 2 moles of HCl
x ----------------- 0.025 moles of HCl
x = (0.025 x 1) / 2
x = 0.0125 moles of HCl
3.- Calculate the atomic weight of the metal
atomic weight ---------------- 1 mol
0.304 g ---------------0.0125 moles
Atomic weight = (1 x 0.304) / 0.0125
Atomic weight = 24.32 g
Answer:
85.5 mmHg is the pressure of the gas sample when the valve is opened.
Explanation:
The combined gas equation is,
where,
= initial pressure of gas in container A = 165 mmHg
= final pressure of gas = ?
= initial volume of gas in container A= 
= final volume of gas = 135 mL + 117 mL = 252 mL
= initial temperature of gas in container A = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
85.5 mmHg is the pressure of the gas sample when the valve is opened.
