First compute the number of grams of manganese metal required to make 21.7 grams of H2.
21.7 g H2 x (1 mole H2/ 2 g H2) x (1 mole Mn/1 mol H2) x (55 grams Mn/1 mol Mn) = 596.75 grams
Now density = mass/volume
7.43 = 596.75/volume
volume = 596.75/7.43 = 80.31 mL
80.31 mL is the amount of manganese needed.
The answer is: 2 NH3 —> N2 + 3 H2
Answer:
Aluminium (aluminum in American and Canadian English) is a chemical element with the symbol Al and atomic number 13. It is a silvery-white, soft, non-magnetic and ductile metal in the boron group. ... Aluminium is remarkable for its low density and its ability to resist corrosion through the phenomenon of passivation.
Explanation:
i did aluminum chemistry
Answer:
Ag(I)C2H3O2 ....................
Silver only has a single valence value (+1) so you really don't need to put the (I) in the chemical formula.
The answer is for this question is c
