The answer it the 3 one I hope this helps
Answer:
3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C
Explanation:
One colligative property is the freezing point depression due the addition of a solute. The equation is:
ΔT=Kf*m*i
<em>Where ΔT is change in temperature = 0.400°C</em>
<em>Kf is freezing point constant of the solvent = 1.86°C/m</em>
<em>m is molality of the solution (Moles of solute / kg of solvent)</em>
<em>And i is Van't Hoff constant (1 for a nonelectrolyte)</em>
Replacing:
0.400°C =1.86°C/m*m*1
0.400°C / 1.86°C/m*1 = 0.215m
As mass of solvent is 280.0g = 0.2800kg, the moles of the solute are:
0.2800kg * (0.215moles / 1kg) = 0.0602 moles of solute must be added.
The mass of ethylene glycol must be added is:
0.0602 moles * (62.10g / mol) =
3.74g of ethylene glycol must be added to decrease the freezing point by 0.400°C
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1. the periodic table is arranged in order of atomic number
Answer: (give brainliest)
proton- a stable particle with positive charge equal to the negative charge of an electron
electron cloud- the system of electrons surrounding the nucleus of an atom.
nucleus- A nucleolus is the largest structure within the nucleus of a eukaryotic cell.
electron- Electrons are the smallest of the particles that make up an atom, and they carry a negative charge.
neutron- a subatomic particle with 0 charge and mass about equal to a proton; enters into the structure of the atomic nucleus.
Explanation:
