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galina1969 [7]
3 years ago
15

Which of the following statements about Ideal Gas Law is supported by Charles's Law?

Chemistry
2 answers:
Hitman42 [59]3 years ago
8 0

Which of the following statements about Ideal Gas Law is supported by Charles's Law?

B) If you decrease the temperature of a gas, its volume will decrease proportionally.

grin007 [14]3 years ago
5 0

Answer:

B

Explanation:

volume occupied by fixed amount of gas is directly proportional to its absolute temperature.

You might be interested in
glucose 6‑phosphate+H2O⟶glucose+Pi glucose 6‑phosphate+H2O⟶glucose+Pi K′eq1=270 K′eq1=270 ATP+glucose⟶ADP+glucose 6‑phosphate AT
ddd [48]

Answer:

-30.7 kj/mol

Explanation:

The standard free energy for the given reaction that is the hydrolysis of ATP is calculated using the formula:  ∆Go ’= -RTln K’eq

where,  

R = -8.315 J / mo

T = 298 K

For reaction,

1. K′eq1=270,

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 270

=  - 8.315 x 298 x 5.59

= - 13,851.293 J / mo

= - 13.85 kj/mol

2. K′eq2=890

∆Go ’= -RTln K’eq

= - 8.315 x 298 x ln 890

=  - 8.315 x 298 x 6.79

=  - 16.82 kj/mol

therefore, total standard free energy

= - 13.85 + (-16.82)

=  -30.7 kj/mol

Thus, -30.7 kj/mol is the correct answer.

6 0
3 years ago
How many moles of KBr are present in 500 ml of a 0.8 M KBr solution?
faltersainse [42]

Answer:

2) 0.4 mol

Explanation:

Step 1: Given data

  • Volume of the solution (V): 500 mL
  • Molar concentration of the solution (M): 0.8 M = 0.8 mol/L

Step 2: Convert "V" to L

We will use the conversion factor 1 L = 1000 mL.

500 mL × 1 L/1000 mL = 0.500 L

Step 3: Calculate the moles of KBr (solute)

The molarity is the quotient between the moles of solute (n) and the liters of solution.

M = n/V

n = M × V

n = 0.8 mol/L × 0.500 L = 0.4 mol

4 0
3 years ago
What is the balanced form of the following equation?. Br2 + S2O32– + H2O → Br1– + SO42– + H+.
zloy xaker [14]
For the equation to be balanced, the Atom's coefficient on the left side and the right side of the equation has to be equal

so, the answer would be : 

Br2 + S2032- + 5H20 -- >  BR2- + 2S02- + H+

Hope this helps
8 0
3 years ago
When a 1.00 L sample of water from the surface of the Dead Sea (which is more than 400 meters below sea level and much saltier t
Harlamova29_29 [7]

Answer: Molarity of MgCl_2 in the original sample was 1.96M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{\text{no of moles}}{\text{Volume in L}}

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{186g}{95g/mol}=1.96

Now put all the given values in the formula of molarity, we get

Molarity=\frac{1.96}{1.00L}

Molarity=1.96mol/L

Thus molarity of MgCl_2 in the original sample was 1.96M

4 0
3 years ago
Please help (30 points)
aleksandrvk [35]

1) is chemical Bonds

3) Conservation of mass

5) compound

hope i helped on the ones i could answer

7 0
3 years ago
Read 2 more answers
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