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3 years ago

15

Which of the following statements about Ideal Gas Law is supported by Charles's Law?

2 answers:

Hitman42 [59]3 years ago

8 0

Which of the following statements about Ideal Gas Law is supported by Charles's Law?

B) If you decrease the temperature of a gas, its volume will decrease proportionally.

grin007 [14]3 years ago

5 0

Answer:

B

Explanation:

volume occupied by fixed amount of gas is directly proportional to its absolute temperature.

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According to the following reaction, what volume in milliliters of 0.244M KCl(aq) solution is required to react exactly with 50.

Elodia [21]

Answer:

There is 86.1 mL of KCl needed

Explanation:

<u>Step 1:</u> Data given

Molarity of KCl = 0.244 M

Volume of a 0.210 M Pb(NO3)2 = 50.0 mL = 0.05 L

<u>Step 2:</u> The balanced equation

2KCl(aq) + Pb(NO3)2(aq) -> PbCl2(s) + 2KNO3(aq)

<u>Step 3:</u> Calculate moles Pb(NO3)2

moles Pb(NO3)2 =molarity * volume

moles Pb(NO3)2 = 0.210 M * 0.05 L

moles Pb(NO3)2 = 0.0105 moles

<u>Step 4:</u> Calculate moles of KCl

For 1 mole of Pb(NO3)2 we need 2 moles of KCl

moles KCl required = 0.0105 * 2 =0.0210 moles

<u>Step 5:</u> Calculate volume of KCl

Volume = moles KCl / molarity KCl

V = 0.0210 moles / 0.244 M=0.0861 L = 86.1 mL

There is 86.1 mL of KCl needed

6 0

3 years ago

The water in a 2500-L aquarium contains 1.25 g of copper. Calculate the concentration of copper in the water in ppm (remember 1

lorasvet [3.4K]

Answer:

0.5ppm

Explanation:

Step 1:

Data obtained from the question.

Volume of water = 2500L

Mas of Cu = 1.25 g

Step 2:

Determination of the concentration of Cu in g/L. This is illustrated below:

Volume of water = 2500L

Mas of Cu = 1.25 g

Conc. of Cu In g/L =?

Conc. g/L = Mass /volume

Conc. of Cu in g/L = 1.25/2500

Conc. of Cu in g/L = 5x10^–4 g/L

Step 3:

Conversion of the concentration of Cu in g/L to ppm. This is illustrated below

Recall:

1g/L = 1000mg/L

Therefore, 5x10^–4 g/L = 5x10^–4 x 1000 = 0.5mg/L

Now, we know that 1mg/L is equal to 1ppm.

Therefore, 0.5mg/L is equivalent to 0.5ppm

6 0

3 years ago

If 3 g of element C combine with 8 g of element D to form compound CD, how many grams of D are needed to form compound CD2?

bija089 [108]

<span>For the answer to the question above,
If 3g of element combines with 8g of D to form CD it means
1 mole of C = 3g
1 mole of D = 8g
hence it forms CD.
So to form CD2 you need 16g of element D
I hope my answer helped you</span>

8 0

3 years ago

Calculate the molar concentration of the Br⁻ ions in 0.51 M MgBr2(aq), assuming that the dissolved substance dissociates complet

Y_Kistochka [10]

MgBr2(aq) is an ionic compound which will have the releasing of 2 Br⁻ ions ions in water for every molecule of MgBr2 that dissolves.
MgBr2(s) --> Mg+(aq) + 2 Br⁻(aq)
[Br⁻] = 0.51 mol MgBr2/1L × 2 mol Br⁻ / 1 mol MgBr2 = 1.0 M
The answer to this question is [Br⁻] = 1.0 M

6 0

3 years ago

How much heat will be given off when 1500 g of water cools down by 20 C? please help and explain:)))

docker41 [41]

Answer:

126000J

Explanation:

From the question given, we obtained the following information:

M = 1500g

C = 4.2J/g°C

ΔT = 20°C

Q =?

Q= MCΔT

Q = 1500 x 4.2 x 20 =

Q = 126000J

7 0

3 years ago