Answer:
on https://www.ck12.org/book/peoples-physics-concepts/section/20.1/
Explanation:
it shows for calcium 45 and maybe a possible equation on 3/4th's scroll down?
Answer:
343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.
Explanation:
A typical carbon–carbon bond requires 348 kJ/mol=348000 J/mol
Energy required to breakl sigle C-C bond:E
![E=\frac{348000 J/mol}{6.022\times 10^{23} mol^{-1}}=5.7788\times 10^{-19} J](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B348000%20J%2Fmol%7D%7B6.022%5Ctimes%2010%5E%7B23%7D%20mol%5E%7B-1%7D%7D%3D5.7788%5Ctimes%2010%5E%7B-19%7D%20J)
![E=\frac{h\times c}{\lambda}](https://tex.z-dn.net/?f=E%3D%5Cfrac%7Bh%5Ctimes%20c%7D%7B%5Clambda%7D)
where,
E = energy of photon
h = Planck's constant = ![6.626\times 10^{-34}Js](https://tex.z-dn.net/?f=6.626%5Ctimes%2010%5E%7B-34%7DJs)
c = speed of light = ![3\times 10^8m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8m%2Fs)
= wavelength of the radiation
Now put all the given values in the above formula, we get the energy of the photons.
![\lambda =\frac{(6.63\times 10^{-34}Js)\times (3\times 10^8m/s)}{5.7788\times 10^{-19} J}](https://tex.z-dn.net/?f=%5Clambda%20%3D%5Cfrac%7B%286.63%5Ctimes%2010%5E%7B-34%7DJs%29%5Ctimes%20%283%5Ctimes%2010%5E8m%2Fs%29%7D%7B5.7788%5Ctimes%2010%5E%7B-19%7D%20J%7D)
![\lambda =3.4398\\times 10^{-7}m=343.98 nm](https://tex.z-dn.net/?f=%5Clambda%20%3D3.4398%5C%5Ctimes%2010%5E%7B-7%7Dm%3D343.98%20nm)
![1 m = 10^{9} nm](https://tex.z-dn.net/?f=1%20m%20%3D%2010%5E%7B9%7D%20nm)
343.98 nm is the longest wavelength of radiation with enough energy to break carbon–carbon bonds.
5.
B.human beings B is correct
<h2>
Answer:</h2>
Option B. Potassium(K).
<h2>
Explanation:</h2>
Electronic configuration of the given elements are:
- Ca - [Ar] 4s²
- K - [Ar] 4s¹
- B - [He] 2s2 2p1
- Kr - [Ar] 3d¹⁰4s²4p⁶
- Krypton(K) have 36 electrons and it is a noble gas and hence all of its shells are completely filled with electrons and hence it will never loose electrons in normal conditions.
- Boron(B) have 5 electrons and 3 electrons in its outer shell. In order to attain a stable configuration it will loose 3 electrons and it is difficult to loose 3 electrons at a time for an atom.
- Calcium(Ca) have 20 electrons and 2 electrons in its outermost shell, in order to attain a stable configuration it will loose 2 electrons. it is quite difficult but easier than Boron.
- Potassium(K) have 21 electrons and 1 electron in its outermost orbit and in order to attain a stable configuration it will loose 1 electron. It is much easier to donate 1 electron than 2 or 3 electrons.
Result: Potassium will loose an electron most easily from the given elements.