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Vlada [557]
3 years ago
7

Find the volume of the solid. 6 cm 8cm 15 cm

Mathematics
1 answer:
Bess [88]3 years ago
8 0

Answer:

720 cm^3

Step-by-step explanation:

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26 out of the 65 magazines at the bookstore are women's magazines. What percentage of the magazines at the bookstore are women's
egoroff_w [7]

The fraction \frac{26}{64} represents the number of women's magazines out of all the other magazines at the book store.

To find what percent of the magazines are women's magazines, we can turn \frac{26}{64} into a percent.

To write a fraction as a percent in lowest terms, first remember that a percent is a ratio of a number to 100 so to write 26/64 as a percent, we need to find a fraction equivalent to 26/64 with 100 in the denominator. We can do this by setting up a proportion.

40% is the answer

IMAGE PROVIDED.

7 0
3 years ago
If 'a' is a number lying between 0 and 1. then which of the following is in increasing order? a) a², a, √a b) a √a ,a² c) a²,√a,
viktelen [127]

Step-by-step explanation:

None of these,

a(under root),a, a(square)

this is the correct answer

5 0
3 years ago
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Legs 3 and 4 are present what is the hypotenuse?
andrew11 [14]

Answer:

4 is hypotenuse

Step-by-step explanation:

6 0
3 years ago
I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a
solong [7]

Answer:

\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}

Step-by-step explanation:

40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4

7 0
3 years ago
What is the same ration of 2/3
frez [133]

Answer:

4/6

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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