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3 years ago

Graph the following inequality. Click on the graph until the correct one appears.

Mathematics

1 answer:

exis [7]3 years ago

5 0

Answer: Its the first one

You draw the graph of the line y=3x+5

but make the line dotted.

Label the line y>3x+5

Note that if instead we hade y≥3x+5 the line would be solid.

If you draw a line parallel to the y-axis through any x-value the value of y can be any on that vertical line that is above but not on the line y=3x+5

. So you end up with a 'feasible' region of solutions for y

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Hence,

$\begin{gathered} 0=3\sqrt{x+3}-6 \\ \\ Collecting\text{ the like terms,} \\ 0+6=3\sqrt{x+3} \\ 6=3\sqrt{x+3} \\ \\ Divide\text{ both sides by 3;} \\ \frac{6}{3}=\sqrt{x+3} \\ 2=\sqrt{x+3} \\ \\ Taking\text{ the square of both sides;} \\ 2^2=x+3 \\ 4=x+3 \\ \\ Collecting\text{ the like terms;} \\ 4-3=x \\ 1=x \\ x=1 \end{gathered}$

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