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Mathematics

1 answer:

ivann1987 [24]3 years ago

8 0

Answer:

Neither the scene nor the positions of the cameras are shown....

Without more detail of the problem, it would seem three different cameras would show the same scene only if they were all in exactly the same place, which is not possible.

Step-by-step explanation:

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Find the difference 17.4-6.102

Nesterboy [21]

11.298 thats the correct answer i used a TI-34 MultiView Calculater.

3 0

3 years ago

Of all the trees planted by a landscaping firm, 45% survive. What is the probability that 13 or more of the 15 trees they just p

Brrunno [24]

<u>ANSWER: </u>

The probability for 13 or more of the 15 trees they just planted will survive is 0.00110702414

<u>SOLUTION: </u>

Given,

The total number of plants is, n=15

The chance of survival of trees is, p=45%.

Probability of getting success p(success) = $\frac{n o \text { of favourable outcomes }}{\text {total possible outcomes}}$

P(success) = $\frac{45}{100}$

P(success) = 0.45

Binomial distribution formula is given as

$\mathrm{P}(\mathrm{X}=\mathrm{x})=\mathrm{n}_{\mathrm{C} \mathrm{x}}(\mathrm{p})^{\mathrm{x}} \cdot(1-\mathrm{p})^{\mathrm{n}-\mathrm{x}}$

In our case, x is greater than or equal to 13, i.e. x $\geq$ 13

The probability for 13 or more of the 15 trees they just planted will survive is given by

$\mathrm{P}(\mathrm{X} \geq 13)=\mathrm{P}(\mathrm{X}=13)+\mathrm{P}(\mathrm{X}=14)+\mathrm{P}(\mathrm{X}=15)$

$\mathrm{P}(\mathrm{X} \geq 13)=\left(15 \mathrm{C}_{13} \times(0.45)^{13} \times(1-0.45)^{15-13}\right.$ + $\left(^{15} \mathrm{C}_{14} \times(0.45)^{14} \times(1-0.45)^{15-14}\right.$ + $\left(15 \mathrm{C}_{15} \times(0.45)^{15} \times(1-0.45)^{15-15}\right.$