a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
Answer:
It would take her 5.85 minutes to run 1 kilometer.
Step-by-step explanation:
76/13= 5.846
565 is the correct answer
For this case, as Josh worked more than 40 hours, he was able to receive a payment
($ 8.20 / h) * (40 h) = 328
1.5(8.20) *8.75 = <span>
<span>107.625
</span></span> 328+107.625= 435.625
the gross earnings for Pruitt are 435.625 $
