9514 1404 393
Answer:
78.5 km
Step-by-step explanation:
Measured at the airport, the angle between the two planes is ...
180° -60° -50° = 70°
The law of cosines tells us the distance between the planes is ...
d = √(50² +80² -2·50·80·cos(70°)) ≈ √6163.84 ≈ 78.5 . . . km
The planes are about 78.5 km apart.
If u do the formula m=y^2-y^1/x^2-x^1 then u have 3-2/6-0 and that simplifies to 1/6 and that is your answer
answer: 1/6
Solution :
The null and alternative hypothesis is given by
Assume that the level of significance, α = 0.05
The t-test statistics is, t = 1.484
Degree of freedom :
df = n - 1
= 14 - 1
= 13
The P-value is given by
P-value = 2P (T>|t|)
= 2P(T>|1.484|)
= 2P(T>1.484)
= 2(=T.DIST.RT(1.484,13))
= 0.05
All you have to do is substitute the 1 into the m for the mile ride:
C = 0.20(1) + 2.00 = 0.20 + 2.00 = 2.20
The charge for 1 mile ride is $2.20.
10 to 6 in simplest form is 1 and 4 6ths
