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Veseljchak [2.6K]
3 years ago
6

19. The population of Jose's town in 1995 was 2400 and the population in 2000 was

Mathematics
1 answer:
Fantom [35]3 years ago
5 0

The linear equation in slope intercept form for population of Jose's town is y = 320x + 2400.

<u>Solution:</u>

Given, the population of Jose's town in 1995 was 2400 and the population in 2000 was 4000,  

Let x represent the number of years since 1995.  

We have to write a linear equation, in slope- intercept form, that represents this data.

Now, let the change in population per year be p.

Then, population in a year = population change per year \times number of years + population in 1995.

⇒population in a year = p\times x + population in 1995

⇒ population in a year = p \times x + 2400

Here we have an case that, population in 2000 is 4000  

Then, number of years since 1995 = 5  

So, 4000 = p \times 5 + 2400 ⇒ 5p = 4000 – 2400 ⇒ 5p = 1600 ⇒ p = 320

Then, our equation will be population in a year = 320x + 2400  

Considering the population in a year as y ⇒ y = 320x + 2400.

Hence, the linear equation in slope intercept form is y = 320x + 2400.

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Binomial probability distribution

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And p is the probability of X happening.

Percentage of students who read less than 850 words per minute.

Pvalue of Z when X = 850. The mean is \mu = 950 and the standard deviation is \sigma = 200

Z = \frac{X - \mu}{\sigma}

Z = \frac{850 - 950}{200}

Z = -0.5

Z = -0.5 has a pvalue of 0.3085.

30.85 of students read less than 850 words per minute.

If 10 students are selected at random, what is the probability that at most two of them would read at less than 850 words per minute

This is P(X \leq 2) when n = 10, p = 0.3085. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.3085)^{0}.(0.6915)^{10} = 0.0250

P(X = 1) = C_{10,1}.(0.3085)^{1}.(0.6915)^{9} = 0.1115

P(X = 2) = C_{10,2}.(0.3085)^{2}.(0.6915)^{8} = 0.2239

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0250 + 0.1115 + 0.2239 = 0.3604

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