Question

a rectangular garden is 7 feet long and 6 feet wide. a second rectangular garden has 3/2 the dimensions of the first garden .what is the percent in change from the first garden to the second garden

Answer 1

Answer:

125%

Step-by-step explanation:

Given: First Rectangular garden has dimension of 7 feet long and 6 feet wide.

           Second Rectangular garden B has 3/2 the dimensions of the first garden.

Considerdering first garden as "A" and second garden as "B".

First lets find the Area for first rectangular garden.

Formula; Area of rectangle= $length\times width$

Area of Graden A= $7\times 6= 42\ feet$

∴ Area of Garden A is 42 feet.

Now, finding area of Garden B.

As given second rectangular garden has 3/2 the dimensions of the first garden.

∴ Length= $\frac{3}{2}\times 7= \frac{21}{2}\ feet$

  Width= $\frac{3}{2} \times 6= 9\ feet$

∴ Area of Garden B= $\frac{21}{2} \times 9= \frac{189}{2}$

 Area of Garden B= 94.5\ feet

Next, finding percent change from the first garden to the second garden.

Difference in area of garden from A to B= $94.5\ feet- 42\ feet= 52.5\ feet$

Percent change= $\frac{difference}{Area\ of\ first\ area}\times 100$

⇒ Percent change= $\frac{52.5}{42} \times 100= 125\%$

Hence, the percent in change from the first garden to the second garden is 125%.