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mario62 [17]
3 years ago
9

How many times 5 will go into 187

Mathematics
2 answers:
Naddik [55]3 years ago
6 0
5 will go into 187 37.4 times
Butoxors [25]3 years ago
3 0
\frac{187}{5} =  \frac{185}{5} +  \frac{2}{5} = 37 + .4 = 37.4
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hammer [34]

Answer:

So you know this picture is a function so it cannot be a or b. The answer is C.

Step-by-step explanation:


6 0
3 years ago
Is the value of the first 4 ten times as great as the value of the second 4 in 4,043? Explain. What can you generalize about the
Ira Lisetskai [31]

As per the the question we need to calculate the value of first 4 multiplied by 10.

Now in the number 4,043, the first 4 is at the thousands place. So the place value of first 4 in the digit 4,043 is 4000.

Multiplying the value of first 4 by 10 we get:

4000 \times 10=40,000

Now, the second 4 in the digit 4,043 is at the tens place. So the place value of second 4 in the digit 4,043 is 40.

We can see that two of them are not equal and the value of first 4 times ten is far greater than the value of second 4.

It can be said that two of the 4s in the digit 4,043 are at two different places, first is at thousands place and second is at tens place. So if the numbers are two places apart their place value will have difference of 100 folds.

5 0
4 years ago
I give ten points and brainliest if you say hi
patriot [66]

Answer:

Hi hope you have a wonderful and blessed day!!!!

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help
mina [271]
"A dozen eggs and a dozen jellybeans" is the one comparison among the following choices given in the question that a teacher would most likely use for describing a mole. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has helped you.
4 0
3 years ago
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Can you guys help we with this question. ​​​​​​
satela [25.4K]

Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

= ((2x)^2 -1/(2x)^2)^5 (a+b)*(a-b) =a2-b2

= (4x^2-1/4(x)^2)^5

now

x =4x^2. ,a = 1/4(x)^2 ,n =5

we have

general term = Cr *x^r *a^(n-r)

= Cr * (4x^2)^r * (1/4(x)^2)^(n-r)

= Cr *4^r * X^2r * 1/( 4^(n-r) *x^(2n-2r)

= Cr * 4^r/4^(n-r) * x^(2r)/x^(2n-2r)

= Cr * 4(2r-n) *x(4r-2n)

now for x^2

4r-2n = 2

4r -10=2

4r =12

r = 3

now for coeff

C(5,3) * 4^(2*3-5)

5!/(3!*(5-3)!) * 4

5*4/(2*1)*4

40

4 0
3 years ago
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