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3 years ago

What is the coefficient of x101y99 in the expansion of (2x − 3y)200?

1 answer:

5 0

You basically multiply 2 by 101 Nd 3 by 99 then but put that equation in parentheses then put the 200 on the outside of the parentheses (2•101-3•99)200

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What are the values of the following expressions? In each line assume that,

MissTica

Answer:

double x = 2.5;

double y = -1.5;

int m = 18;

int n = 4;

string s = "Storm";

string t = "Watch";

The output of the expression "x + n*y - (x+n)*y" is "6.25".

and the output of expression "m/n + m%n" is "6".

Explanation:

for the first expression,

x + n*y - (x+n)*y ,put value of every variables in it.

=2.5+4*(-1.5)-(2.5+4)*(-1.5)

=2.5-6.0-(6.5*(-1.5)

=-3.5+9.75

=6.25

for the second expression,

m/n + m%n, put value of every variables in it.

=18/4 +18%4

=4+2 ("/ will give quotient and % will give remainder")

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3 years ago

Should spreadsheets be used to keep an address list for holiday cards?<br> YES<br> ONO<br> Hurry pls

kodGreya [7K]

Answer:

because spreadsheet is used for calculation not for writing address

5 0

2 years ago

1. If Earth's plates are constantly moving, why don't we need to update the locations of -

Dmitriy789 [7]

Answer:

Because the tectonic plates are moving so slowly in such small incraments that it would take a while before there was any noticable change.

Explanation:

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3 years ago

. The BEST description of a proprietary database is one that

AVprozaik [17]

Is free to the public

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4 years ago

Host A sends real time voice to Host B over a packet switched network. Host A first converts the analogue voice signal to a digi

DiKsa [7]

Answer:

Time required is 0.007 s

Explanation:

As per the question:

Analog signal to digital bit stream conversion by Host A =64 kbps

Byte packets obtained by Host A = 56 bytes

Rate of transmission = 2 Mbps

Propagation delay = 10 ms = 0.01 s

Now,

Considering the packets' first bit, as its transmission is only after the generation of all the bits in the packet.

Time taken to generate and convert all the bits into digital signal is given by;

t = $\frac{Total\ No.\ of\ packets}{A/D\ bit\ stream\ conversion}$

t = $\frac{56\times 8}{64\times 10^{3}}$ (Since, 1 byte = 8 bits)

t = 7 ms = 0.007 s

Time Required for transmission of the packet, t':

$t' = \frac{Total\ No.\ of\ packets}{Transmission\ rate}$

$t' = \frac{56\times 8}{2\times 10^{6}} = 2.24\times 10^{- 4} s$

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3 years ago