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ElenaW [278]
4 years ago
10

A pole vaulter runs forward, plants his pole, rises in the air and lands. What point represents his greatest amount of gravitati

onal potential energy?
A) when he initially lands

B) as he runs forward to plant the pole

C) just before he starts to fall to the ground

D) after take-off as the pole expands and lifts the vaulter toward the bar
Physics
2 answers:
natta225 [31]4 years ago
7 0
<span>C) Just before he starts to fall to the ground Remember that "gravitational potential energy" is the energy the object potentially has if it were to drop from the current height. So let's look at the options and see what's correct. A) When he initially lands * He's currently near the lowest height. So his gravitational potential energy is quite low. So this is the wrong choice. B) As he runs forward to plant the pole * He's on the ground. So has almost no height. So almost no gravitational potential energy. So this too is wrong. C) Just before he starts to fall to the ground * Ah. He's at his maximum height. So his potential gravitational potential energy is maximized. This is the correct choice. D) After take-off as the pole expands and lifts the vaulter toward the bar * He's at a low height. So once again, this is a bad choice.</span>
kodGreya [7K]4 years ago
5 0

Answer:

C)  just before he starts to fall to the ground

Explanation:

The maximum amount of gravitational potential energy is when the vaulter is at the highest position in the air, just as before he starts to fall to the ground. There is potential energy when he plants the pole, but that is converted to kinetic energy as it lifts him upward.

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dsp73

Answer:

(i) See attached image for the drawing

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Explanation:

First try to write all forces in  vector component form:

The force F1 acting at 45 degrees would have multiplication factors of \frac{\sqrt{2} }{2} on both axes, to take care of the sine and cosine projections. Therefore, the:

x-component of F1 is    F1_x=12\,\sqrt{2} \frac{\sqrt{2} }{2} =12\,\,N

y-component of F1 is    F1_y=12\,\sqrt{2} \frac{\sqrt{2} }{2} =12\,\,N

As far as force F2, it is given already in x and y components, then:

x-component of F2 = 8 N

y-component of F2 = -6 N (negative meaning pointing down the y-axis)

Force F3 has only component (upwards) in the y-direction

x-component of F3 = 0 N

y-component of F3 =14 N

The additions of all these component by component, gives the resultant force (R) acting on the 5 kg mass:

x-component of R = 12 + 8 = 20 N

y-component of R = 12 + 14 - 6 = 20 N

Therefore, the acceleration that the mass receives due to this force is given in component form as:

x-component of acceleration: 20 N / 5 kg = 4\,\,\,m/s^2

y-component of acceleration: 20 N / 5 kg = 4\,\,\,m/s^2

Now we can calculate the components of the velocity of this mass after 2 seconds of being accelerated by this force, using the formula of acceleration times time:

x-component of the velocity is:     v_x=4\,*\,2=8\,m/s

y-component of the velocity is:     v_y=4\,*\,2=8\,m/s

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Answer:

A) move into the left lane to pass the motorcycle

Explanation:

According to law, when it is needed to pass other vehicles, it requires you to only pass other vehicles on the left (using the left lane).  

When passing a motorcyclist, remember to give him/her the same full lane width as other vehicles. Never drive in the same lane with a motorcyclist, even if the lane is wide enough to fit your vehicle and the motorcyclist.

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Answer:

travilng on a curve in the road

Explanation:

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Explanation:

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