1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
borishaifa [10]
3 years ago
9

Which term means the distance between two bridge supports?

Physics
1 answer:
Ad libitum [116K]3 years ago
5 0

The best answer is b - span.

A span is the distance between two bridge supports The supports may be towers, columns, or even the wall of a canyon.

There are many kinds of bridges  but they all fall into three types namely beam, arch and suspension. The major difference between these three kinds of bridges is the distance that each can cross in  a single span.

For example, a modern beam bridge is likely to span a distance of 200 feet, a modern arch can span 800 or 1000feet,  and a modern suspension bridge can span up to 7000ft.


You might be interested in
A velocity vs. time graph starts at 0 and ends at 10 m/s, stretching over a time- span of 15 s with constant acceleration. What
Alex777 [14]

Answer:

75m

Explanation:

6 0
3 years ago
I feel death among us
liberstina [14]

same but who knows how 2021 might go

3 0
3 years ago
Read 2 more answers
A train 471 m long is moving on a straight track with a speed of 75.1 km/h. The engineer applies the brakes at a crossing, and l
hram777 [196]

Answer:

t = 37.6 s

Explanation:

As we know that train is initially moving with the speed

v_i = 75.1 km/h

now we know that

v_i = 20.86 m/s

now the final speed of the train when it crossed the crossing

v_f = 15 km/h

v_f = 4.17 m/s

now we can use kinematics here

v_f^2 - v_i^2 = 2 a d

4.17^2 - 20.86^2 = 2 a(471)

a = -0.44 m/s^2

Now the time to cross that junction is given as

v_f - v_i = at

4.17 - 20.86 = a(-0.44)

t = 37.6 s

4 0
2 years ago
Interactive LearningWare 10.1 reviews the concepts involved in this problem. A spring stretches by 0.0161 m when a 3.74-kg objec
yKpoI14uk [10]

Answer:

m = 3.91 kg

Explanation:

Given that,

Mass of the object, m = 3.74 kg

Stretching in the spring, x = 0.0161 m

The frequency of vibration, f = 3.84 Hz

When the object is suspended, the gravitational force is balanced by the spring force as :

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{3.74\times 9.8}{0.0161}

k = 2276.52 N/m

The frequency of vibration is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

m=\dfrac{k}{4\pi^2f^2}

m=\dfrac{2276.52}{4\pi^2\times (3.84)^2}

m = 3.91 kg

So, the mass of the object is 3.91 kg. Hence, this is the required solution.

8 0
3 years ago
Which of the following can be determined by studying the spectrum of a star?
Alex73 [517]
The right answer is 
  
all of the above 
 
good luck

3 0
3 years ago
Other questions:
  • The ‘hubble constant, h0’ is used to determine
    13·2 answers
  • Which of the following criteria can help Linda classify gases as greenhouse gases?
    5·2 answers
  • 700 miles away, to try out his luck. The ride there with the wind takes four hours. A few months later almost broke he heads bac
    6·1 answer
  • A charge of 28 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 4 x 104 N
    12·1 answer
  • ITS EASY TRUST ME!!!!
    5·2 answers
  • se lanza un cuerpo desde el origen con velocidad horizontal de 40 m/s, y con un ángulo de 60º. calcular la máxima altura y el al
    7·1 answer
  • Number of vibrations (waves) in an amount of time
    13·1 answer
  • This distance from the Earth to the Sun given above is a standard for measuring other distances in the solar system and is calle
    6·1 answer
  • If you were rolling a toy car down an incline, what would happen if you made the incline steeper? Explain why this happens using
    13·1 answer
  • A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically dr
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!