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klasskru [66]
3 years ago
7

\nljbvjlsfhglskhg;skgh;sfjs;ojsr;ogjs;dofhs;dkhs;lifhns

Physics
1 answer:
vladimir1956 [14]3 years ago
8 0
That is nonsense, also known as jibberish
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What is the purpose of draeing a free-body diagrams
maria [59]
In order to see what forces are acting upon an object in every direction.
3 0
3 years ago
To view an interactive solution to a problem that is similar to this one, select Interactive Solution 7.24. A 0.0146-kg bullet i
Vinil7 [7]

Answer:

0.25223 seconds.

Explanation:

m_1 = Mass of bullet = 0.0146 kg

m_2 = Mass of block = 2.55 kg

v = Combined velocity

u_1 = Velocity of bullet = 816 m/s

g = Acceleration due to gravity = 9.81 m/s²

As linear momentum is conserved

m_1u_1 + m_2u_2 =(m_1 + m_2)v

Now u_2=v as the block (with the bullet in it) reverses direction and rises,

m_1u_1 + m_2v =(m_1 + m_2)v\\\Rightarrow m_1u_1=(m_1 + m_2)v-m_2v\\\Rightarrow 0.0146\times 816=(0.0146 + 2.55)v-(-2.55v)\\\Rightarrow 11.9136=2.2646v+2.55v\\\Rightarrow 11.9136=4.8146v\\\Rightarrow v=\frac{11.9136}{4.8146}\\\Rightarrow v=2.47447\ m/s

Equation of motion

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{2.47447-0}{9.81}\\\Rightarrow t=0.25223\ s

The time t is 0.25223 seconds.

3 0
3 years ago
A person is standing on a scale in an unmoving elevator. The elevator starts to move upwards at 1 m/s squared. Is the scale read
timama [110]

Answer: GREATER

Explanation:when elevator does not move it reads weight of the person . when elevator moves up let apparent weight be F . W acts downwards so net force is F-W

HENCE

F-W =ma

F= ma+W

AS a= 1 m/s^2

F = m (1)+W

HENCE GREATER

7 0
3 years ago
A 310-g air track cart is traveling at 1.25 m/s and a 260-g cart traveling in the opposite direction at 1.33 m/s. What is the sp
UNO [17]

Answer:

v_{CM}=0.0732\ m/s

Explanation:

given,

mass of the cart 1, m₁ = 310 g

speed of car 1 , v₁ = 1.25 m/s

mass of cart 2, m₂ = 260 g

speed of cart 2, v₂ = -1.33 m/s

speed of center of mass

v_{CM}=\dfrac{m_1v_1 + m_2 v_2}{m_1 + m_2}

v_{CM}=\dfrac{0.31\times 1.25 +0.26\times (-1.33)}{0.31+0.26}

v_{CM}=\dfrac{0.0417}{0.57}

v_{CM}=0.0732\ m/s

Hence, speed of center of mass of the system is equal to 0.0732 m/s

7 0
3 years ago
If you are swimming upstream (i.e., against the current), at what speed does your friend on the shore see you moving?
Alex777 [14]
Could be very slow since they’re basically going against the current which is hard so will be going slow
7 0
4 years ago
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