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Archy [21]
3 years ago
9

In a sample of 50 randomly selected students at a school, 38 students eat breakfast every morning. There are 652 students in the

school. using these results, predict the number of students that eat breakfast.
A. 76
B.123
C.247
D.496
Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0
For the sample:
\frac{38}{50} = 0.76 = 76\%

Applying this to the whole population:

652 \times \frac {38}{50} = 495.52

Since we can't have "0.52 of a person" we roudn to the neares whole, or 496.
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Laurence, the stadium manager, spends $22,000 on a broadcast TV ad, $30,000 on a cable TV ad, and $6,000 on a radio ad. What per
Vesnalui [34]

38 % of amount is spent on broadcast TV advertising

<em><u>Solution:</u></em>

Given that,

Amount spend on broadcast TV ad = $ 22, 000

Amount spend on cable TV ad = $ 30, 000

Amount spend on radio ad = $ 6000

To find: percentage of broadcast TV advertising

Total amount = $ 22, 000 + $ 30, 000 + $ 6000

Total amount = $ 58000

percentage of broadcast TV advertising = \frac{\text{ amount spend on broadcast tv}}{\text{ total amount}} \times 100

\rightarrow \frac{22000}{58000} \times 100\\\\\rightarrow 0.3793 \times 100 = 37.93 \approx 38

Thus 38 % of amount is spent on broadcast TV advertising

7 0
3 years ago
SOooo .. I'm doing my Geometry DBA on edgenuity and i'm ready to quit.
Akimi4 [234]
No way don’t give up brotha
7 0
3 years ago
PLEASE HELP ME!!!!!
NARA [144]

Answer:

c -13

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
I need help with coming up with equation
Natali5045456 [20]

Let's call a child's ticket c and an adult's ticket a. From this, we can say:

c + a = 116,

since 116 tickets are sold in total.


Now, we are going to need to find another equation (the problem asks us to solve a systems of equations). This time, we are not going to base the equation on ticket quantity, but rather ticket price. We know that an adult's ticket is $17,000, and a child's ticket is thus

\$17000 \cdot (1 - \dfrac{1}{4}) = \$12750.


Given these values, we can say:

17000a + 12750c = 1653250,

since each adult ticket a costs 17,000 and each child's ticket c costs 12,750, and these costs sum to 1,653,250.


Now, we have two equations:

17000a + 12750c = 1653250

c + a = 116


Let's solve:

17000a + 12750c = 1653250

a = 116 - c

  • Find a on its own, which will allow us to substitute it into the first equation

17000(116 - c) + 12750a = 1653250

  • Substitute in 116 - c for a

1972000 - 17000c + 12750c = 1653250

  • Apply the Distributive Property

1972000 - 4250c = 1653250

  • Combine like terms

4250c = 318750

  • Subtract 1972000 from both sides of the equation and multiply both sides by -1

c = 75


We have now found that 75 child's tickets were sold. Thus,

75 + a = 116 \Rightarrow a = 116 - 75 = 41,

41 adult tickets were sold as well.


In sum, 41 adult tickets were sold along with 75 child tickets.

6 0
3 years ago
Dolev shared his pretzels equally among 5 friends. If each friend received 7 pretzels, how many pretzels did Dolev have? Select
gtnhenbr [62]

Answer:

B. Multiply by 5 on both sides of the equation. C. 7 × 5 = 35. E. Dolev had 35 pretzels.

Step-by-step explanation:

B. get p by itself

C. if each received 7 and there was 5 people, 5 times 7 would be the total of pretzels

E. 5 times 7 equals 35.

6 0
3 years ago
Read 3 more answers
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