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Aneli [31]
3 years ago
10

Given FH is the median of EFG find x, EH, and HG. ​

Mathematics
1 answer:
Marianna [84]3 years ago
4 0
Yeah his answer is correct Good job!
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3
adoni [48]

9514 1404 393

Answer:

  (d)  2 11/12

Step-by-step explanation:

  \dfrac{2}{3}-\dfrac{5}{4}+\dfrac{7}{2}=\dfrac{2}{3}+\left(\dfrac{14}{4}-\dfrac{5}{4}\right)=\dfrac{8}{12}+\dfrac{27}{12}=\dfrac{35}{12}=\boxed{2\dfrac{11}{12}}

7 0
3 years ago
7|r+5|-2=12 what is the formula? Solve the equation.
SIZIF [17.4K]

Start with

7|r+5|-2=12

Add 2 to both sides:

7|r+5|=14

Divide both sides by 7:

|r+5|=2

Which is true if

r+5=\pm 2

If we choose the positive alternative, we have

r+5=2 \iff r=3

Otherwise, we have

r+5=-2 \iff r=-7

6 0
3 years ago
What is the slope of (12,-18) and (11,12)? Please I’m very confused.
Lesechka [4]

Answer:

-30

Step-by-step explanation:

\boxed{slope =  \frac{y1 - y2}{x1 - x2} }

where (x₁, y₁) is the first coordinate and (x₂, y₂) is the second coordinate.

Slope

=  \frac{12 - ( - 18)}{11 - 12}

=  \frac{12 + 18}{ - 1}

= -30

6 0
3 years ago
Obtain the equation of the straight line which makes equal intercepts on the axes an passes through the point of intersection of
vagabundo [1.1K]
Hey, here it is…
Hope it helps

3 0
3 years ago
Graduated cylinders and beakers what are they and whats the difference
Verizon [17]
Cylinders are lengthy and tall and beakers are short and fat
6 0
3 years ago
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