If the acceleration due to gravity at the surface of planet x is double the value of earth's, how does planet x's mass compare t
1 answer:
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The force required to extend a rod increases as the cross sectional area
increases.
The rod that experiences the largest force is <u>rod B</u>
Reason:
The elongation of a rod by the application of a force is given by the
following formula;
From the above equation, we have that the elongation is inversely
proportional to the cross sectional area, such that the extension of a rod by
a given force reduces as the cross sectional area of the rod increases.
Therefore, the force required to extend the length of a rod by a specific
amount increases as the cross sectional area of the rod increases,
indicating that the rod with the largest cross sectional area require the
most force and therefore, experiences the largest force.
The rod that experiences the largest force is the rod with the largest cross
sectional area, which is <u>rod B</u>
Learn more here:
The given problem can be exemplified in the following diagram:
Since there is no friction or any other external force, the only force acting in the direction of the movement is the component of the weight of the block, therefore, applying Newton's second law:
Replacing the values:
We may cancel out the mass:
Using the gravity constant as 9.8 meters per square second:
Solving the operations:
Therefore, the acceleration is 6.3 meters per square second.
Answer:
2(maximum), -2(minimum), -2(maximum).
Explanation:
V(t)= 2πcos πt--------------------------------------------------------------------------------(1).
Therefore, there is a need to integrate v(t) to get S(t).
S(t)= 2×sinπt + C ------------------------------------------------------------------------------(2).
Applying the condition given, we have s(0)= 0.
S(0)= 2sin ×π(0) + C.
Which means that; 0+C= 0. That is; C=0.
S(t)= 2 sin πt.
The mass moves to its highest positions at time,t=half(1/2=.5) and time,t=2.5.
Take note that; sin(π/2) = sin(5π/2) = 1 .
Also, the mass moves to its lowest position at time,t=(3/2); also, sin(3π/2) = -1.
Therefore, we have that 2 maximum; -2 minimum and -2 maximum.
