Flammable and combustible liquids themselves do not burn. It is the mixture of their vapours and air that burns. Gasoline, with a flashpoint of -40°C (-40°F), is a flammable liquid. Even at temperatures as low as -40°C (-40°F), it gives off enough vapour to form a burnable mixture in air.
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Answer:
It doesn't give light
Explanation:
No Flowing of electricity
Answer:
4 A
Explanation:
The relationship between current, voltage and resistance in a circuit is given by Ohm's law:
![V=RI](https://tex.z-dn.net/?f=V%3DRI)
where
V is the voltage
R is the resistance
I is the current
The equation can also be rewritten as
![I=\frac{V}{R}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BV%7D%7BR%7D)
from which we see that the current is inversely proportional to the resistance, R.
In this problem, the initial current is I = 8 A. Then the resistance is doubled:
R ' = 2R
So the new current is
![I'=\frac{V}{R'}=\frac{V}{2R}=\frac{1}{2}(\frac{V}{R})=\frac{I}{2}=4 A](https://tex.z-dn.net/?f=I%27%3D%5Cfrac%7BV%7D%7BR%27%7D%3D%5Cfrac%7BV%7D%7B2R%7D%3D%5Cfrac%7B1%7D%7B2%7D%28%5Cfrac%7BV%7D%7BR%7D%29%3D%5Cfrac%7BI%7D%7B2%7D%3D4%20A)
so the current is halved.
The decibel system of sound intensity operates by a logarithmic scale, meaning that sound intensity increases exponentially in relation to the decibel rating.
For decibels, the equation between intensity and the dB equivalent is:
dB = 10log(i),
where “i” is the intensity of the sound. The ten in front of the log means that an increase in ten dB results in a tenfold increase in sound intensity; for example, a 30 dB sound is ten times softer than a 40 dB sound.
In this case, a sound with a dB of 80 would be 1000 times more intense than a 50 dB sound, so the decibel rating of B is 80.
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