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xz_007 [3.2K]
3 years ago
14

In a region of space, a magnetic field points in the +x-direction (toward the right). Its magnitude varies with position accordi

ng to the formula Bx=B0+bx, where B0 and b are positive constants, for x≥0. A flat coil of area A moves with uniform speed v from right to left with the plane of its area always perpendicular to this field. Part A What is the emf induced in this coil while it is to the right of the origin?
Physics
1 answer:
otez555 [7]3 years ago
3 0

Answer:

E=Abv

Explanation:

We are given that

B_x=B_0+bx

For x\geq 0

Area of coil=A

Speed=v

We have to find the emf induced in the coil while it is to the right of the origin.

We know that induced emf

E=-\frac{d\phi}{dt}

\phi=BA

E=-\frac{d(A(B_0+bx)}{dt}

E=-A(b)\frac{dx}{dt}

We know that

v=-\frac{dx}{dt}

Substitute the value

E=Abv

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