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snow_tiger [21]
2 years ago
8

A hockey puck with a mass of 0.159 kg slides over the ice. The puck initially slides with a speed of 4.75 m/s, but it comes to a

rough patch in the ice which slows it down to a speed of 2.35 m/s. How much energy is dissipated as the puck slides over the rough patch
Physics
1 answer:
Anton [14]2 years ago
5 0

Answer:

The energy dissipated as the puck slides over the rough patch is 1.355 J

Explanation:

Given;

mass of the hockey puck, m = 0.159 kg

initial speed of the puck, u = 4.75 m/s

final speed of the puck, v = 2.35 m/s

The energy dissipated as the puck slides over the rough patch is given by;

ΔE = ¹/₂m(v² - u²)

ΔE = ¹/₂ x 0.159 (2.35² - 4.75²)

ΔE = -1.355 J

the lost energy is 1.355 J

Therefore, the energy dissipated as the puck slides over the rough patch is 1.355 J

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alina1380 [7]
Chapter name please then I can answer
3 0
2 years ago
A strand of 10 lights is plugged into a outlet. How can you determine if the lights are connected in series or parrel
NeTakaya

Answer:

C) Unscrew one light. If the other lights turn off, it's a series circuit.

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

A strand of 10 lights is plugged into an outlet. How can you determine if the lights are connected in series or parallel? A) Unscrew one light. If the other lights stay on, it's a series circuit. B) Unplug the strand. If the first light stays on, it's a series circuit. C) Unscrew one light. If the other lights turn off, it's a series circuit. D) Cut the strand in half. If the plugged in half stays on, it's a series circuit.

SERIES CIRCUIT

In this circuit, the components there are in the same path, the entire circuit has the same current, each of the components posses different voltage drop. Hence, failure of one components to work, there will be break in entire circuit then other components cease to work.

PARALLEL CIRCUIT

This circuit has equal voltage drop across all the components, any problem in a component will not has effect on other components.

Therefore, if one want to determine if a light connection is in series or in parallel, one of the light can be unplugged if others stop working it means it's series, if other works it's parallel.

5 0
2 years ago
Electrical energy is converted into kinetic energy in
Vanyuwa [196]
The answer would be a motor. If thats one of the options, it was for me :)
6 0
3 years ago
An object of mass 10.0kg is released at point A, slidesto the bottom of the 30° incline, then collides with ahorizontal massless
Elenna [48]

Answer:

Explanation:

Potential energy lost by mass = mgh

= 10 x 9.8 x 2 = 196 J

a ) If v be velocity of mass at the bottom , its kinetic energy will be stored in spring as elastic energy

= 1/2 m v² = 1/2 k x² , k is spring constant , x is compression , m is mass falling down

.5 x 10 v² = .5 x 500 x .75²

v = 5.3 m /s

b ) kinetic energy of mass at the bottom

= /2 m v²

= .5 x 10 x 5.3²

= 140.45 J

energy lost by mass while coming down

=potential energy at the top - kinetic energy at bottom

=  196 - 140.45

= 55.55 J .

This is equal to negative work done by friction

work done by friction = - 55.55 J

c ) Since there will be no loss of energy in compression and extension of spring so , no loss of kinetic energy will take place of mass . So it wil have same velocity that is 5.3 m /s while on its return journey.

d ) kinetic energy at the bottom = 140.45

loss of energy by friction again

= 140.45  - 55.55

= 84.9 J

If h be the height attained

mgh = 84.9

10 x 9.8 x h = 84.9

h = .866 m

( We have assumed that loss of energy in return journey will be same due to friction . )

6 0
3 years ago
In an LRC circuit, why does the sum of the voltages around the circuit not equal the applied voltage as kirchhoff’s rule require
wel

Kirchhoff's loop rule is always true.

The foundation of circuit analysis is Kirchhoff's Laws for current and voltage. We have the fundamental set of tools required to begin evaluating circuits with these two principles, In an RLC circuit, the most fundamental elements of a resistor, inductor, and capacitor are connected across a voltage supply.

Learn more about Kirchhoff loop rule here-  

brainly.com/question/15003023

#SPJ4

5 0
1 year ago
Read 2 more answers
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