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PolarNik [594]
3 years ago
13

Determine the x- and y- intercepts for the graph defined by the given equation. y = 7x + 3 a. x-intercept is ( 3, 0) y-intercept

is (0, negative StartFraction 3 Over 7 EndFraction) c. x-intercept is (0, negative StartFraction 3 Over 7 EndFraction) y-intercept is ( 3, 0) b. x-intercept is (negative StartFraction 3 Over 7 EndFraction, 0) y-intercept is (0, 3) d. x-intercept is (3, 0) y-intercept is (negative StartFraction 3 Over 7 EndFraction, 0)
Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

x-intercept is (-3/7, 0) and the y-intercept is at (0, 3)

Step-by-step explanation:

Given the function y = 7x + 3

The x-intercept occurs at y = 0. Substituting y = 0 into the expression, we will have:

0 = 7x + 3

7x + 3 = 0

7x = -3

x = -3/7

Similarly, the y-intercept occurs at x = 0. Substituting x = 0 into the expression, we will have:

y = 7(0) + 3

y = 0 + 3

y = 3

Hence the x-intercept is (-3/7, 0) and the y-intercept is at (0, 3)

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zvonat [6]

Answer:

Option B is correct

Step-by-step explanation:

Given:

f(x) = -20x^2 +14x +12 and

g(x) = 5x - 6

We need to find f/g and state its domain.

f/g = -20x^2 +14x +12/5x - 6

Taking -2 common from numerator:

f/g = -2(10x^2 - 7x - 6) / 5x -6

Factorize 10x^2 - 7x - 6= 10x^2 - 12x +5x -6

Putting in the above equation

f/g = -2(10x^2 - 12x +5x -6)/ 5x -6

f/g = -2(2x(5x-6) + 1 (5x-6)) / 5x-6

f/g = -2 ( (2x+1)(5x-6))/5x-6

cancelling 5x-6 from numerator and denominator

f/g = -2(2x+1)

f/g = -4x -2

The domain of the function is set of all values for which the function is defined and real.

So, our function g(x) = 5x -6 and domain will be all real numbers except x = 6/5 as denominator will be zero if x=5/6 and the function will be undefined.

So, Option B is correct.

8 0
3 years ago
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cluponka [151]
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adelina 88 [10]
I don’t think it issss
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algol13
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