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PolarNik [594]
3 years ago
13

Determine the x- and y- intercepts for the graph defined by the given equation. y = 7x + 3 a. x-intercept is ( 3, 0) y-intercept

is (0, negative StartFraction 3 Over 7 EndFraction) c. x-intercept is (0, negative StartFraction 3 Over 7 EndFraction) y-intercept is ( 3, 0) b. x-intercept is (negative StartFraction 3 Over 7 EndFraction, 0) y-intercept is (0, 3) d. x-intercept is (3, 0) y-intercept is (negative StartFraction 3 Over 7 EndFraction, 0)
Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

x-intercept is (-3/7, 0) and the y-intercept is at (0, 3)

Step-by-step explanation:

Given the function y = 7x + 3

The x-intercept occurs at y = 0. Substituting y = 0 into the expression, we will have:

0 = 7x + 3

7x + 3 = 0

7x = -3

x = -3/7

Similarly, the y-intercept occurs at x = 0. Substituting x = 0 into the expression, we will have:

y = 7(0) + 3

y = 0 + 3

y = 3

Hence the x-intercept is (-3/7, 0) and the y-intercept is at (0, 3)

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Answer:

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Step-by-step explanation:

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3 years ago
The Walker family and the Goodman family are going to the cinema. The Walkers pay £22 for 2 adult tickets and 1 child ticket. Th
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The children's ticket is $6 and an adults ticket is $8.

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4 years ago
Approximate 650.385 to 1 decimal place
stealth61 [152]
650.385 rounded to one decimal place is 650.4

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3 years ago
Read 2 more answers
Evaluate the upper and lower sums for f(x) = 1 + x2, −1 ≤ x ≤ 1, with n = 3 and 4.
Elenna [48]
I'm going to assume that your function is f(x) = 1 + x^2    (NOT x2).

I suspect you're trying to estimate the "area under the curve of f(x) = 1 + x^2.  You need to use this or a similar description to explain what you're doing.

Also, you need to specify whether you want "left end points" or "right end points" or "midpoints."  Again I must assume you want one or the other (and will assume that you meant "left end points").  

First, let's address the case n=3.  You must graph f(x) = 1 + x^2 between -1 and +1.     We will find the "lower sum," using "left end points."  The 3 x-values are {-1, -1/3, 1/3}.  Evaluate the function f(x) = 1 + x^2 at these 3 x-values.  Keep in mind that the interval width is 2/3.
The function (y) values are {0, 2/3, 4/3}.

Sorry, Michael, but I must stop here and await clarification from you regarding what you've been told to do in this problem.  Otherwise too much guessing (regarding what you meant) is necessary.  Please review the original problem and ensure that you have copied it exactly as presented, and also please verify whether this problem does indeed involve estimating areas under curves between starting and ending x-values.
7 0
3 years ago
a vehicle factory manufactures cars. The unit cost C (the cost in dollars to make each car) depends on the number of cars made.
timofeeve [1]

Answer:

8,567

Step-by-step explanation:

Given the cost function expressed as C(x)=0.7x^2- 462 x + 84,797

To get the minimum vaklue of the function, we need to get the value of x first.

At minimum value, x = -b/2a

From the equation, a = 0.7 and b = -462

x = -(-462)/2(0.7)

x = 462/1.4

x = 330

To get the minimum cost function, we will substitute x = 330 into the function C(x)

C(x)=0.7x^2- 462 x + 84,797

C(330)=0.7(330)^2- 462 (330)+ 84,797

C(330)= 76230- 152460+ 84,797

C(330) = 8,567

Hence the minimum unit cost is 8,567

7 0
3 years ago
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