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mamaluj [8]
3 years ago
7

Pls help is due tomorrow and if u help i will give u brainliest

Mathematics
1 answer:
Reil [10]3 years ago
6 0

Answer:

Search it up

Step-by-step equation:

Just search up the website at the bottom of the paper.

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What would the distance be of a crater of 4300 feet in diameter use 3.14 pi\
oksano4ka [1.4K]
Answer : 13502 ft
Circumference of crater 2 pi r
Diameter = 4300
Radius = (4300/2)
Distance = 2 × 3.14 × (4300/2)
= 13502 ft


Hope it helped!
4 0
3 years ago
What is the halfway fraction between 3/5 and 7/10
Dmitry [639]
The answer is 13/20. So 3/5 is equal to 6/10 so you're looking for the fraction that's half of 7/10 and 6/10 which is 6.5/10 but you can't use decimals in a fraction so you multiply both sides by 10 which would equal 65/100 and simply, and that would be 13/20.
7 0
3 years ago
Suppose that X is a random variable with mean 30 and standard deviation 4. Also suppose that Y is a random variable with mean 50
Vladimir79 [104]

Answer:

a) Var[z] = 1600

    D[z] = 40

b) Var[z] = 2304

    D[z] = 48

c) Var[z] = 80

    D[z] = 8.94

d) Var[z] = 80

    D[z] = 8.94

e) Var[z] = 320

    D[z] = 17.88

Step-by-step explanation:

In general

V([x+y] = V[x] + V[y] +2Cov[xy]

how in this problem Cov[XY] = 0, then

V[x+y] = V[x] + V[y]

Also we must use this properti of the variance  

V[ax+b] = a^{2}V[x]

and remember that

standard desviation = \sqrt{Var[x]}

a) z = 35-10x

   Var[z] = 10^{2} Var[x] = 100*16 = 1600

   D[z] = \sqrt{1600} = 40

b) z = 12x -5

   Var[z] = 12^{2} Var[x] = 144*16 = 2304

   D[z] = \sqrt{2304} = 48

c) z = x + y

   Var[z] =  Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94  

d) z = x - y

   Var[z] =  Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80

   D[z] = \sqrt{80} = 8.94

e) z = -2x + 2y

   Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320

  D[z] = \sqrt{320} = 17.88

   

7 0
3 years ago
Solve this equation. (4w-28)+(11w+13)=180
Kitty [74]
Solve for w by simplifying both sides of the equation, then isolating the variable.

w=13
7 0
3 years ago
Please help soon I need it​
Gekata [30.6K]

Answer:

ok

Step-by-step explanation:

4 0
2 years ago
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