All categories

3 years ago

What are the Factors of 24?

Mathematics

2 answers:

inessss [21]3 years ago

8 0

1,2,3,4,6,8,12,24 are the factors

DIA [1.3K]3 years ago

7 0

1,2,3,4,6,8,12,24 are the factors. Hope it helped!!!!!

You might be interested in

I have two fair dice both numbered 1 to 6. I throw both dice and add both numbers together. What is the probability that the num

Alex17521 [72]

Answer:7/36

Step-by-step explanation:

Firstly, I would draw a table to visually see what the outcomes are. There are many methods but this is what i find to be the easiest so here it goes!!!

I hope the pic helps! If you have any questions feel free to ask!

7 0

3 years ago

Lucia is putting cookies into bags. She has 35 cookies. She wants to put 3 cookies in each bag. She divides to find out how many

skad [1K]

Answer:

I think D.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Emily tossed a die onto a black and red checkerboard. what is the probability that it will land with a value of 2, on a red squa

Oxana [17]

1/2 becuase they are in between i think hope this helps

7 0

3 years ago

Read 2 more answers

Solve the linear inequality below.

quester [9]

Answer:

x > 3

Step-by-step explanation:

6 0

2 years ago

A playground is being designed where children can interact with their friends in certain combinations. If there is 1 child, ther

mariarad [96]

<h2>Answer:</h2>

Recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

<h2>Step-by-step explanation:</h2>

In the question,

The number of interaction for 1 child = 0

Number of interactions for 2 children = 1

Number of interactions for 3 children = 5

Number of interaction for 4 children = 14

So,

We need to find out the pattern for the recursive equation for the given conditions.

So,

We see that,

$a_{1}=0\\a_{2}=1\\a_{3}=5\\a_{4}=14\\$

Therefore, on checking, we observe that,

$a_{n}=a_{n-1}+(n-1)^{2}$

On checking the equation at the given values of 'n' of, 1, 2, 3 and 4.

At,

n = 1

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{1}=a_{1-1}+(1-1)^{2}\\a_{1}=0+0=0\\a_{1}=0$

which is true.

At,

n = 2

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{2}=a_{2-1}+(2-1)^{2}\\a_{2}=a_{1}+1\\a_{2}=1$

Which is also true.

At,

n = 3

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{3}=a_{3-1}+(3-1)^{2}\\a_{3}=a_{2}+4\\a_{3}=5$

Which is true.

At,

n = 4

$a_{n}=a_{n-1}+(n-1)^{2}\\a_{4}=a_{4-1}+(4-1)^{2}\\a_{4}=a_{3}+9\\a_{4}=14$

This is also true at the given value of 'n'.

Therefore, the recursive equation for the pattern followed is given by,

$a_{n}=a_{n-1}+(n-1)^{2}$

3 0

3 years ago