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3 years ago

PLEASE HELP ASAP This probability distribution shows the

Mathematics

1 answer:

ivolga24 [154]3 years ago

3 0

Answer:

The probability is 0.29

Step-by-step explanation:

Firstly, we need to know the total number of retakes

That is simply the sum of the frequencies

we have this as;

27 + 29 + 18 + 14 + 12 = 100

so the probability of retaking exactly once will be the number of 1 retakes divided by total

That would be 29/100 = 0.29

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

3 years ago

Pedro is building a playground in the shape of a right triangle he wants to know the area of the playground to help him decide h

shusha [124]

Answer:

Amount of sand=Area of triangle(ABC)=1/2*AB*BC

Dimension of rectangle as length=BC and breadth=AB

Step-by-step explanation:

Given:

Pedro building a playground in shape of right angled triangle.

To Find:

How much sand he need to buy

And if playground changed to rectangle what will be the dimensions.

Solution:

Consider a ΔABC be the play ground vertex of playground,

And AB and BC be the sides making right angle.

The sand required to fill ground will be the amount of are covered by the ABC triangle.

So,

Area Of triangle(ABC)=1/2* base* height

Here base will be BC and height =AB

Therefore Area of Triangle(ABC)=1/2*BC*AB

Depending on the lengths of base and height amount of sand will be decided.

Now,

For Rectangle dimensions,

We know that if same sized triangles composes each other forms a rectangle.

It requires two triangle to form one rectangle as follows

(Refer the attachment)

Same sized Triangle ACD is imposed on it to from rectangle ABCD.

So dimension for rectangle will be same as the triangle

Dimension=length and breadth

i.e. length=base of triangle=BC

Breadth=Height of triangle=AB

i.e Breadth =AB.

5 0

3 years ago