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Harlamova29_29 [7]
2 years ago
7

Help, please I would appreciate it.

Mathematics
1 answer:
Veronika [31]2 years ago
3 0
At firt we should solve what is h(0)
h(0)=0^2+2
h(0)=2
So then you should take the h(0) answer to g(x) and the result is g(2)= -2-5=-7
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Need help! Will mark u brainliest for the right answer!
kirill115 [55]

To find the perimeter of this blue figure, add together the shown lengths of the six sides.  

The three measurements on the top have the LCD 4, so we combine 14 3/4, 4 2/4 and 8 2/4.  The sum is 26 7/4, or 27 3/4, or 27.75.

The three measurements on the bottom share the LCD 5, so we can immediately combine them, obtaining 32 8/5, or 33 3/5, or 33.60.

Combining 27.75 and 33.60 results in 61.35, or 61 35/100, or 61 7/20.

The perimeter of the given figure is 61 7/20.

3 0
3 years ago
A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use of one particular cust
Fiesta28 [93]

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the given set of values

321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320

STEP 2: Write the formula for calculating the Standard deviation of a set of numbers

\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ where\text{ }x_i\text{ are data points,} \\ \bar{x}\text{ is the mean} \\ \text{n is the number of values in the data set} \end{gathered}

STEP 3: Calculate the mean

\begin{gathered} \bar{x}=\frac{\sum ^{}_{}x_i}{n} \\ \bar{x}=\frac{\sum ^{}_{}(321,397,559,454,475,324,482,558,369,513,385,360,459,403,498,477,361,366,372,320)}{20} \\ \bar{x}=\frac{8453}{20}=422.65 \end{gathered}

STEP 4: Calculate the Standard deviation

\begin{gathered} S\tan dard\text{ deviation=}\sqrt[]{\frac{\sum^{}_{}(x_i-\bar{x})^2}{n-1}} \\ \sum ^{}_{}(x_i-\bar{x})^2\Rightarrow\text{Sum of squares of differences} \\ \Rightarrow10332.7225+657.9225+18591.3225+982.8225+2740.52251+9731.8225+3522.4225+18319.6225+2878.3225 \\ +8163.1225+1417.5225+3925.0225+1321.3225+386.1225+5677.6225+2953.9225+3800.7225 \\ +3209.2225+2565.4225+10537.0225 \\ \text{Sum}\Rightarrow108974.0275 \\  \\ S\tan dard\text{ deviation}=\sqrt[]{\frac{111714.55}{20-1}}=\sqrt[]{\frac{111714.55}{19}} \\ \Rightarrow\sqrt[]{5879.713158}=76.67928767 \\  \\ S\tan dard\text{ deviation}\approx76.68 \end{gathered}

Hence, the standard deviation of the given set of numbers is approximately 76.68 to 2 decimal places.

STEP 5: Calculate the First and third quartile

\begin{gathered} \text{IQR}=Q_3-Q_1 \\  \\ To\text{ get }Q_1 \\ We\text{ first arrange the data in ascending order} \\ \mathrm{Arrange\: the\: terms\: in\: ascending\: order} \\ 320,\: 321,\: 324,\: 360,\: 361,\: 366,\: 369,\: 372,\: 385,\: 397,\: 403,\: 454,\: 459,\: 475,\: 477,\: 482,\: 498,\: 513,\: 558,\: 559 \\ Q_1=(\frac{n+1}{4})th \\ Q_1=(\frac{20+1}{4})th=\frac{21}{4}th=5.25th\Rightarrow\frac{361+366}{2}=\frac{727}{2}=363.5 \\  \\ To\text{ get }Q_3 \\ Q_3=(\frac{3(n+1)}{4})th=\frac{3\times21}{4}=\frac{63}{4}=15.75th\Rightarrow\frac{477+482}{2}=\frac{959}{2}=479.5 \end{gathered}

STEP 6: Find the Interquartile Range

\begin{gathered} IQR=Q_3-Q_1 \\ \text{IQR}=479.5-363.5 \\ \text{IQR}=116 \end{gathered}

Hence, the interquartile range of the data is 116

3 0
1 year ago
Can anyone explain how to solve this?
eduard
I’m not 100 percent sure someone can comment on this and confirm but when it’s written like a fraction it means division. If they gave you the meaning of each variable (the letters) multiply each variable by each coefficient (the number next to the variable). Multiply all of those. Then divide it by the product of 4 and the variable

Hope this helped!
8 0
3 years ago
Carolyn sells homemade candles. Write an expression for her total revenue if she sells x candles for $5 each
jok3333 [9.3K]

Answer:

I think it would be X x 5 = Y

Step-by-step explanation:

5 0
3 years ago
9* – 5( 3*+1) + 54= 0
Kobotan [32]

Answer:

43=0

this should be the answer :)

6 0
3 years ago
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