<span>Form a sequence that has two arithmetic means between -13 and 89. a. -13, 33, 43, 89 c. -13, 21, 55, 89 b. -18, -36, -72, -144 d. -18, -81, -144
Solution:
Since it has to be between -13 and 89, letter d and b are not anymore considered to be the answer.
for a:
33-(-13)=46=d
43-33=10=d the value for this d is different from the two sequence,
89-43=46=d
they have different value for d, thus this is not the answer!
for c:
21-(-13)=34=d
55-21=34=d
89-55=34=d
they have the same value for d, thus the correct answer is </span><span> c. -13, 21, 55, 89</span>
The expression is given by:

So we need to find an equivalent equation for this problem. Then, we will apply some mathematical rules:
Extracting the common factor 1/4, then:

Or extracting the common factor -1/4, then:

So, comparing these solutions with the answers about, there is no any answer that matches.
Hello,
I suppose equations are:
x+y=3 (1)
x+2y=9 (2)
(2)-(1)==>y=6
(1)==>x=3-6
x=-3, y=6
Sol={(-3,6)}
Answer:


Step-by-step explanation:
Solve Using the Quadratic Formula
4x^2 + 8x − 5 = 0
Use the quadratic formula to find the solutions.
−b ± √b^2 − 4 (ac)
-------------------------
2a
Substitute the values a = 4, b = 8, and c = −5 into the quadratic formula and solve for x.
−8 ± √82 − 4 ⋅ (4 ⋅ −5)
-------------------------
2 ⋅ 4
Simplify the numerator.
Raise 8 to the p ower of 2.
−8 ± √64 − 4 ⋅ 4 ⋅ −5
x= ---------------------------
2 ⋅ 4
Multiply −4 by 4.
−8 ± √64 − 16 ⋅ −5
x = -------------------------
2 ⋅ 4
Multiply −16 by −5.
−8 ± √64 + 80
x = -------------------
2 ⋅ 4
Add 64 and 80.
−8 ± √144
x = --------------
2 ⋅ 4
Rewrite 144 as 12^2.
−8 ± √122
x = ------------
2 ⋅ 4
Pull terms out from under the radical, assuming positive real numbers.
multiply 2 by 4
−8 ± 12
x= ------------
8
simplify
−2 ± 3
x= ---------
2
The final answer is the combination of both solutions.
x= 1/2, -5/2
Hope this helped!
78 * 3/4 hour,
it is 6 hours