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yaroslaw [1]
3 years ago
13

ASAP HELP! MATRICES!

Mathematics
1 answer:
Gemiola [76]3 years ago
4 0

2A = \left[\begin{array}{ccc}8&18\\26&10\end{array}\right]

Step-by-step explanation:

Given

A = \left[\begin{array}{ccc}4&9\\13&5\end{array}\right]

We have to find 2A which means all the elements of the matrix have to be multiplied by the integer 2

So,

2A = 2\left[\begin{array}{ccc}4&9\\13&5\end{array}\right]\\= \left[\begin{array}{ccc}2(4)&2(9)\\2(13)&2(5)\end{array}\right]\\=\left[\begin{array}{ccc}8&18\\26&10\end{array}\right]

Hence,

2A = \left[\begin{array}{ccc}8&18\\26&10\end{array}\right]

Keywords: Matrices,  Multiplication of matrices

Learn more about matrices at:

  • brainly.com/question/669100
  • brainly.com/question/663692

#LearnwithBrainly

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What is the inverse of f(x)=x^4+7 for x&gt;0 where function g is the inverse of function f?<br> -
Ann [662]

Answer:

g(x) = \sqrt[4]{x-7},~ x\geq 7

Step by step explanation:

y= f(x) = x^4+7\\\\\text{Replace x with y and solve for y:}\\\\~~~~~~~x = y^4 +7\\\\\implies y^4 = x-7\\\\\implies y = \pm\sqrt[4]{x-7}\\\\ \implies f^{-1}(x) = \pm\sqrt[4]{x-7}

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3 years ago
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2x(squared) + 23x-19=0
Helen [10]
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for ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

given
2x^2+23x-19=0
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