Answer:
The price after the discount would be $315.
The solution to the given differential equation is yp=−14xcos(2x)
The characteristic equation for this differential equation is:
P(s)=s2+4
The roots of the characteristic equation are:
s=±2i
Therefore, the homogeneous solution is:
yh=c1sin(2x)+c2cos(2x)
Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:
yp=Axsin(2x)+Bxcos(2x)
If you take the second derivative of the equation above for yp , and then substitute that result, y′′p , along with equation for yp above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side, sin(2x) , you will find:
A=0
B=−14
Therefore,
yp=−14xcos(2x)
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Yes it does because when you graph it the next point would be (1,0).
Answer:
The Figure for Right triangle is below,
Therefore , 15 unit length represents BC.
Step-by-step explanation:
Given:
Consider a right triangle ABC, Such that
To Find:
BC = ?
Solution:
In Right Angle Triangle ABC, Cosine and Tangent identity
BUT,
....Given
On Comparing,
Adjacent side to angle A = AB = 15
Opposite side to angle A = BC = 8
Hypotenuse = AC =17
Also Pythagoras theorem is Satisfies,
The Figure for Right triangle is below,
Therefore , 15 unit length represents BC.
