Ask question

Ask question

All categories

3 years ago

15

WHOEVER GETS IT RIGHT GETS BRAINLIEST

2 answers:

lakkis [162]3 years ago

7 0

Hello there!

(75x - 49y) - (62x +18y)

We wanna start by distributing the negative sign to those on the right side

75x - 49y - 62x - 18y

Combine like terms

75x - 62x - 49y - 18y

= 13x - 67y

Kobotan [32]3 years ago

5 0

Hi there! The answer is B.

$(75x - 49y) - (62x + 18y) =$

First work out the parenthesis.
$75x - 49y - 62x - 18y =$

Next collect the terms.
$13x - 67y$

The answer is B.

You might be interested in

Write an equation for the trend line in slope-intercept form. <br><br> Please help me !

anastassius [24]

Answer:

y=0.05x+0.25

Step-by-step explanation:

.25/5 is slope---- divide

.25 is y-int

5 0

3 years ago

What are the next 3 terms of the sequence? 3, 12, 48, 192

dimaraw [331]

199 idk I hope you get it right tho

4 0

3 years ago

Read 2 more answers

Find the vector, not with determinants, but by using properties of cross products. k × (i − 3j)

sergey [27]

$\mathbf k\times(\mathbf i-3\mathbf j)=(\mathbf k\times\mathbf i)-3(\mathbf k\times\mathbf j)$
$=\mathbf j-3(-\mathbf i)$
$=3\mathbf i+\mathbf j$

3 0

3 years ago

Special Triangles

Ugo [173]

Answer:

see explanation

Step-by-step explanation:

Using the cosine and tangent trigonometric ratios and the exact values

cos30° = $\frac{\sqrt{3} }{2}$ and tan30° = $\frac{1}{\sqrt{3} }$ , then

cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{6}{m}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

$\sqrt{3}$ × m = 12 ( divide both sides by $\sqrt{3}$ )

m = $\frac{12}{\sqrt{3} }$ ← rationalise by multiplying numerator/ denominator by $\sqrt{3}$ )

m = $\frac{12}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = $\frac{12\sqrt{3} }{3}$ = 4 $\sqrt{3}$

-------------------------------------------------------------------------------

tan30° = $\frac{opposite}{adjacent}$ = $\frac{n}{6}$ = $\frac{1}{\sqrt{3} }$ ( cross- multiply )

$\sqrt{3}$ × n = 6 ( divide both sides by $\sqrt{3}$ )

n = $\frac{6}{\sqrt{3} }$ ← rationalise the denominator

n = $\frac{6}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = $\frac{6\sqrt{3} }{3}$ = 2 $\sqrt{3}$

-----------------------------------------------------------------------------------

7 0

3 years ago

The regular admission price for an amusement park is $72. For a group of 15 or more, the admission is reduced by $25 per person.

Lena [83]

20 people because 500÷25=20 and 72x20 is 1440 and 1440-500=940$

6 0

3 years ago