Question

What is the distance between p(-300, 200) and Q(500, 400)?

Answer 1

Answer:

200 √17

Step-by-step explanation:

distance between two points (x,y) and (x',y')

D² = (x' - x)² + (y' - y)²

D² = (500 - (-300))² + (400 - 200)² = 640000 + 40000 = 680000

D = √680000 = √4 x 17 x 10000 = 200 √17