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Nataly_w [17]
3 years ago
7

Multiply (2x-5)(3x2-4x+2)

Mathematics
1 answer:
WITCHER [35]3 years ago
8 0

Answer:The answer is 183, hope I helped.  

You might be interested in
David has a triangular prism that has an equilateral base. Also, the base of the prism is of the same length as its height. Pick
Komok [63]

Answer:

a) Triangle

b) Rectangle

Step-by-step explanation:

A triangular prism that has an equilateral base and a height with the same length as the base of the prism.

a) Shape from horizontal slicing

A plane parallel to the base of a triangular prism will  intersect a cross section that is the same shape as its  bases. So the cross section of the horizontal slicing is an equilateral triangle (all the sides of the triangle are equal).

b) Shape from vertical slicing

If the triangular prism is sliced vertically, the resulting shape would be a rectangle with a length that is the same as the base of the prism.

4 0
3 years ago
Can someone please help me?
Citrus2011 [14]

Answer:

A. 14

Step-by-step explanation:

Okay, so the square is 25 and the circle is 39.

For example, if you take out the square from the circle, that leaves the shaded areas.

39-25=14

14 is your answer.

Cheers!

4 0
3 years ago
Which characteristics will prove that ΔDEF is an acute, isosceles triangle?
ololo11 [35]

Answer:

  a.  segment DE and segment EF are congruent to each other but not to segment DF, and their slopes are not related.

Step-by-step explanation:

In order for a triangle to be isosceles, two of the line segments must be congruent. (eliminates choices C and D)

If the slopes of the congruent segments are negative reciprocals of each other, the triangle is a right triangle, not an acute triangle. (eliminates choice B)

With choices B, C, D eliminated, we are left with choice A.

__

However, <em>that necessary description is not sufficient</em> to constrain the triangle to be an acute triangle. In order for the triangle to be acute, the third side must be less than √2 times the length of either of the congruent sides.

The correct answer is "none of the above."

3 0
3 years ago
Let W= { (x, y, z) |x=1|; y, z ∈ℝ } Prove that W is a subspace of ∈ℝ<br> How can I resolve this ?
Nataly [62]

Answer:

W is not a subspace.

Step-by-step explanation:

Notice that (-1,2,2) and (-1,5,3) are both elements of W. Because its x coordinate, x = -1, satisfy the condition |x| = 1.

but (-1,2,2) + (-1,5,3) = (-2,7,5) do not belongs to W. Because its first coordinate, x =-2, do not satisfy |x| = 1.  

5 0
3 years ago
How to solve this because i think my steps are wrong ?
wlad13 [49]

Replace x with 3:

h(3) = (3^2 -4) /2

= (9-4 ) / 2

= 5/2

8 0
4 years ago
Read 2 more answers
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