Answer:
![cos^2\theta + sin^2\theta = 1](https://tex.z-dn.net/?f=cos%5E2%5Ctheta%20%2B%20sin%5E2%5Ctheta%20%3D%201)
Step-by-step explanation:
Given
![(\frac{b}{r})^2 + (\frac{a}{r})^2](https://tex.z-dn.net/?f=%28%5Cfrac%7Bb%7D%7Br%7D%29%5E2%20%20%2B%20%28%5Cfrac%7Ba%7D%7Br%7D%29%5E2)
Required
Use the expression to prove a trigonometry identity
The given expression is not complete until it is written as:
![(\frac{b}{r})^2 + (\frac{a}{r})^2 = (\frac{r}{r})^2](https://tex.z-dn.net/?f=%28%5Cfrac%7Bb%7D%7Br%7D%29%5E2%20%20%2B%20%28%5Cfrac%7Ba%7D%7Br%7D%29%5E2%20%20%3D%20%28%5Cfrac%7Br%7D%7Br%7D%29%5E2)
Going by the Pythagoras theorem, we can assume the following.
- a = Opposite
- b = Adjacent
- r = Hypothenuse
So, we have:
![Sin\theta = \frac{a}{r}](https://tex.z-dn.net/?f=Sin%5Ctheta%20%3D%20%5Cfrac%7Ba%7D%7Br%7D)
![Cos\theta = \frac{b}{r}](https://tex.z-dn.net/?f=Cos%5Ctheta%20%3D%20%5Cfrac%7Bb%7D%7Br%7D)
Having said that:
The expression can be further simplified as:
![(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1](https://tex.z-dn.net/?f=%28%5Cfrac%7Bb%7D%7Br%7D%29%5E2%20%20%2B%20%28%5Cfrac%7Ba%7D%7Br%7D%29%5E2%20%20%3D%201)
Substitute values for sin and cos
becomes
![cos^2\theta + sin^2\theta = 1](https://tex.z-dn.net/?f=cos%5E2%5Ctheta%20%2B%20sin%5E2%5Ctheta%20%3D%201)
Yes I love this problem so good
Answer:
The answer is C. 2/3
Step-by-step explanation:
Remember that, for independent events, the probability that both occurr is the product of the individual probabilities.
a) Probability of being contacted: 78% = 0.78
Probaility of refusing: 1 - 22% = 1 -0.22 = 0.78
Combined probability: 0.78*0.78 = 0.6084
b) The probability of failing to contact or making contact and not geeting them to agree 1 - the probability of contacting and getting them to agree.
The probabilityof contacting and getting them to agree is 0.78*0.22 = 0.1716
The the answer to this question is 1 - 0.1716 = 0.8284
If you mean 4 / (11/8)
= 4 * 8/11
= 32/11
= 2 10/11
= 2.909