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kramer
3 years ago
14

I need help on this question i will give points to whoever answer its​

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

x=34

Step-by-step explanation:

2x =68

-----------             (68 divided by 2 is 34)

2        2

x=34

Bezzdna [24]3 years ago
5 0

Answer:

the answer would be A. x=34

Step-by-step explanation:

to solve for x in this equation, you need to get x all by itself to do this, you need to remember that what you do to one side of the equation, you must do to the other. so:

we start with 2x=68, and to get rid of the 2 in front of the x, divide each side by 2.

2x/2=68/2

so now x is alone:

x=68/2

and now divide 68 by 2, which is 34.

so, x=34

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Hola me podrían ayudar por favor. Convertir las fracciones a decimales y ubicar a los decimales en la recta numérica. a. 2/3 b.
NISA [10]

Answer:

Step-by-step explanation:

a decimal

2/3 = 0.7

8/5 = 1.6

-5/2 = -2.5

7/4 = 1.8

9/2 =  4.5

-11/3 = -3.7

13/5 = 2.6

-7/4 = -1.8

Esto es solo un bosquejo del número, usando un gráfico, use 0.1 para una unidad en la recta numérica.

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  |    |     |      |     |       |      |       |     |     |     |    |       |     |     |      |     |     |       |            

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Which statement is true about judy's method?
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A. Judy made a mistake between Steps 1 and 2
To factor x^{2} - 16, you have to factor it as (x-2)(x+2)(x-4), not (x-2)(x+8), because that will leave an extra 6x because of 8x - 2x. 
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Maths functions question!!
Marina86 [1]

Answer:

5)  DE = 7 units and DF = 4 units

6)  ST = 8 units

\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units

8)  x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

  • f(x)=-x+3
  • g(x)=x^2-9
  • A = (3, 0)  and C = (-3, 0)

<h3><u>Part (5)</u></h3>

Points A and D are the <u>points of intersection</u> of the two functions.  

To find the x-values of the points of intersection, equate the two functions and solve for x:

\implies g(x)=f(x)

\implies x^2-9=-x+3

\implies x^2+x-12=0

\implies x^2+4x-3x-12=0

\implies x(x+4)-3(x+4)=0

\implies (x-3)(x+4)=0

Apply the zero-product property:

\implies (x-3)= \implies x=3

\implies (x+4)=0 \implies x=-4

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

\implies f(-4)=-(-4)=7

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

<h3><u>Part (6)</u></h3>

To find point S, substitute the x-value of point T into function g(x):

\implies g(4)=(4)^2-9=7

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

\implies ST=y_S-y_T=7-(-1)=8

Therefore, ST = 8 units.

<h3><u>Part (7)</u></h3>

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x.  To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

\implies f(x)-g(x)=QR

\implies -x+3-(x^2-9)=\dfrac{45}{4}

\implies -x+3-x^2+9=\dfrac{45}{4}

\implies -x^2-x+\dfrac{3}{4}=0

\implies -4\left(-x^2-x+\dfrac{3}{4}\right)=-4(0)

\implies 4x^2+4x-3=0

\implies 4x^2+6x-2x-3=0

\implies 2x(2x+3)-1(2x+3)=0

\implies (2x-1)(2x+3)=0

Apply the zero-product property:

\implies (2x-1)=0 \implies x=\dfrac{1}{2}

\implies (2x+3)=0 \implies x=-\dfrac{3}{2}

As the x-value of points M, Q and P is negative, x = -³/₂.

Length OM is the difference between the x-values of points M and the origin O:

\implies x_O-x_m=o-(-\frac{3}{2})=\dfrac{3}{2}

Therefore, OM = ³/₂ units.

<h3><u>Part (8)</u></h3>

The values of x for which g(x) ≥ 0 are the values of x when the parabola is above the x-axis.

Therefore, g(x) ≥ 0 when x ≤ -3 and x ≥ 3.

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