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Jlenok [28]
3 years ago
13

A student evaluated -4 + x for x = 9 1/2 and got an answer of 5 1/2. What might the student have done wrong?

Mathematics
2 answers:
larisa86 [58]3 years ago
8 0
The student did not complete the BEDMAS formula properly
Vikki [24]3 years ago
3 0
-4+x=9.5
x=13.5

The student might have subtracted 9.5-4, which results in the answer 5.5. The correct answer is 13.5.
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In a school auditorium, the number of chairs in a row is the same as the number of rows of chairs. If there are 529 chairs in th
BartSMP [9]

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How do you get the domain and range of a bar graph
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X is the domain and y is the range 

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3 years ago
In parallelogram WXYZ, what is CY?<br> CY=___ ft
dangina [55]
<span>The correct answer is 11 ft.

Explanation:
The diagonals of a parallelogram bisect each other. This means that the portion marked x+4 is the same length as the portion marked 2x-7; this gives us the equation x+4=2x-7.

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6 0
4 years ago
Read 2 more answers
I’m need this worked out step by step by tonight
Pie

9514 1404 393

Answer:

  -3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

  -7 ≤ (3x -5)/2 ≤ 7

Multiply all parts by 2.

  -14 ≤ 3x -5 ≤ 14

Add 5 to all parts.

  -9 ≤ 3x ≤ 19

Divide all parts by 3.

  -3 ≤ x ≤ 19/3

_____

<em>Additional comment</em>

If you subtract 7 from both sides of the given inequality, it becomes ...

  |(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

__

For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

  |f(x)| < (some number) . . . . or ≤

If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

  |f(x)| > g(x)   ⇒   f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0

Any solutions to these inequalities must respect their domains.

8 0
3 years ago
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